Hi Mrs. Brown,
Question #9 : You have a 120v circuit (L1-N) with two loads in series, R1 and R2. R1 = 20 ohms; R2 = 40 ohms. What is the voltage drop across R1?
My original answer was 40 volts as calculated below.
The test response deemed my answer incorrect.
Went back to double check my calculations and from what I can see they are correct.
Anything you could add to this to clarify?
Combine the resistance for 1 total = 20 Ohms + 40 Ohms = 60 Ohms
I = E/R 120/60 = 2Amps in circuit.
Voltage Drop
E = I X R I(2amps) x 20(R1) = R1 Voltage Drop is 40 Volts
Many thanks,
David
