Everardo Gonzalez

[Everardo Gonzalez]

Now, could you explain me little more the question # 7 I will appreciate your assistance. Why I do fail those 2 questions?

[Everardo Gonzalez]

Yes I was witching the video in unit #5 again. Thank you so much Susan.

[Everardo Gonzalez]

then I was right when I type 6.7 ohms as an answer?

[Everardo Gonzalez]

Not really could you explain me
Please?

[Everardo Gonzalez]

Sorry Susan I change your name

[Everardo Gonzalez]

Hi Carol:
Not suppose to calculate amps?
I did because that’s what I have in my notes. Am I wrong?

[Everardo Gonzalez]

Hi Susan:
I have watched the Equivalent Resistance unit in order to solve the question #5 Please let me know if I am correct. The expected equivalent resistance
of the two circuits is:
R(eq) = 1/ R1 + R2 = 1/10 = 0.1 1/20 = 0.05 0.1 + 0.05 = 0.15 1/0.15 = 6.7 Ohms. I = E/R = 120/10 + 6.7 + 20 = 36.7 120/36.7 = 3.27 amps.

I appreciate your valuable Help.

Everardo Gonzalez.

P. S. During the weekend I will re study the questions #7 and # 9

[Everardo Gonzalez]

Hi Susan:
That’s me again Everardo Gonzalez. Question: Is there any where in this Core Class any practice unit? because I am better learner in the practice than in the theory

[Everardo Gonzalez]

Got it let me rewatch the unit #6 and the midterm help page and then I will go back to you. I really appreciate your help Susan.

[Everardo Gonzalez]

Yes I do thanks to you. About the #9 was my answer correct? In figure #2 the L2 is conectes to the heating element and to the N that’s why it has 120 VAC

[Everardo Gonzalez]

No it does not have any voltage drop.

[Everardo Gonzalez]

The detector is the shunt and the Main is the shunted?

[Everardo Gonzalez]

The detector

[Everardo Gonzalez]

Yes So that means the Main is a shunt?

[Everardo Gonzalez]

yes it does 120 VAC because It is in serial circuit with the booster on left hand and the N on the right hand.

[Author]

Posts