andrew anderson

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May 8, 2021 at 10:38 pm in reply to: replacing the compressor and filter(unable to move any further into the course ) #21854
andrew anderson
Hello Susan unfortunately the button is not visible because the video appears to be blocking it (its like the video is to large or something i hope thats makes sense )
April 22, 2021 at 3:32 pm in reply to: system approach to trouble questions 4 & 2 #21778
andrew anderson
Hello Susan , My apology for not following up sooner and thanks for answering my question .
December 1, 2020 at 11:03 pm in reply to: Mod. 3, Unit 1, Q. 2 – Timer Voltage Drop #20979
andrew anderson
I almost forgot to answer the question No absolutely not no current flowing means 0 voltage drop, thanks
December 1, 2020 at 10:53 pm in reply to: Mod. 3, Unit 1, Q. 2 – Timer Voltage Drop #20978
andrew anderson
Thanks Susan Sorry I just received your message I’m also workineg a full time job , You are awesome 👌
November 28, 2020 at 9:42 pm in reply to: Mod. 3, Unit 1, Q. 2 – Timer Voltage Drop #20960
andrew anderson
HI SUSAN, Yes I remember there must be current flowing through the load to measure a voltage drop, however for some reason I was thinking that current flow was the results of having a potential difference across the load which would be L1 to L2, and if we new the resistance of the load we could then use ohms law to find the current I=E÷R ?
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Viewing 5 posts - 16 through 20 (of 20 total)