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Aaahhhhh!!!!! Now that makes perfect sense to me. Thank you so much for explaining.
I see. Thanks for explaining.
You got me on that one. Sometimes my mind is on one track and I’m not looking at the big picture.
ThanksScott, I just went back to the course and you did actually mention shunt in your text answer to the bonus question. I should have read on before commenting here. Sorry about that.
Scott, I had a similar question as top why when the operating T-stat is closed, why then does the Timer motor not run since there is basically a parallel circuit where at the L2 side of the parallel circuit, the wires then come together and then go thru the heater and then to L2. Until I read above where you say “as explained in the lesson, when the cycling thermostat closes, it shunts the timer motor.” Then it clicked in my mind. However you don’t actually say that it shunts the timer motor in the video. Saying that just helped me understand it immediately. I don’t know why but it made sense. You do say in the video how the timer motor has L1 on both sides of it so there is no potential but I wasn’t quite getting it. So I did what you said and checked out the Student Forum and was able to find the answer without having to post my own question. I don’t know if adding that “shunting” statement to the video would help anyone else or not. Probably not, but it did help me. Thanks, John Hedger.
Which direction would the diaphragm move if the unregulated pressure increased?
I may not have answered correctly or stated it the way I wanted to. But could you tell me if the following statements are correct. If not, please show me where. I want to understand the operation of the regulator properly.According to my understanding, the answer could be different depending on in what state the appliance’s burner valve, for example, is in. Open or Closed.
If the burner valve downstream was closed, with unregulated gas applied to the inlet of the regulator, no gas would be flowing. With no gas flowing, the regulator valve attached to the diaphragm would be closed. Increasing the unregulated pressure wouldn’t move the valve and diaphragm at all other than make the valve closed tighter.
If the burner valve downstream was open, with unregulated gas applied to the inlet of the regulator, gas would be flowing. With gas flowing, the regulator valve would be open and modulating up and down slightly to keep the outlet pressure constant. Increasing the unregulated pressure a little might cause the modulating valve (and diaphragm) to move up to a slightly higher position, but continue to modulate in order to keep the outlet pressure constant.
And if the unregulated inlet pressure was increased enough, I guess it could overcome the spring tension enough to move the diaphragm up enough to close the regulator valve, which would stop the flow of gas.
Also, As far as the terminals go, what do you have crimped on since you don’t know what terminals you’d be connecting them to?
This was a great video. It helped me a lot in understanding the timer chart. But also, I really enjoyed the 10 step tango process that you used in troubleshooting the problem and how you wrote out your notes next to each step and then progressed to the next step. Just for my information on this particular video, if there was no humming heard, would it be correct in assuming that power wasn’t getting to the high run winding of the motor either?
Thanks, John (Hedgemo60) -
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