fbpx

Joshua Godawa

Forum Replies Created

Viewing 6 posts - 1 through 6 (of 6 total)
  • Author
    Posts
  • February 6, 2019 at 4:14 pm in reply to: Question 4. #15327
    Joshua Godawa

      Thank you. Got it now. The test really makes you think so that you understand the material.

      February 5, 2019 at 4:18 pm in reply to: Question 4. #15321
      Joshua Godawa

        [answer hidden]

        E= I*R
        then times that by ohms. if done correctly the 3 (10, 20 , 40) ohms should come to total 120v.

        February 4, 2019 at 6:51 pm in reply to: midterm exam question #15314
        Joshua Godawa

          mid term question 7.
          fan motor current? should not change because current will still flow the same regardless if he element is open or closed?

          element would decrease due to no power the element?

          February 4, 2019 at 6:36 pm in reply to: Midterm Question 8 #15313
          Joshua Godawa

            so ignitor, booster and main have to equal 120v?

            February 4, 2019 at 6:17 pm in reply to: Question 4. #15312
            Joshua Godawa

              So with out giving the answer to the form, ill just use the first resistance of 10 ohms. I=E/r 120/10=12 I=12

              E=I*r E=12*10=120 E=120v drop. The same applies to the other two loads. Am I on the right path?

              January 30, 2019 at 12:39 pm in reply to: midterm exam question #15227
              Joshua Godawa

                Question #7: Here is a circuit showing the convection element and convection fan motor in an electric wall oven. The power supply is 120 VAC.

                I just don’t get what im doing wrong. I re-watched the videos, drew out diagrams even tried googling other resources. Please explain what im doing wrong.

              • Author
                Posts
              Viewing 6 posts - 1 through 6 (of 6 total)