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It should read open , if the switch is bad . It should read zero volts ,if the switch is good. If it’s a load. It should have a voltage drop, if the load is good and zero if it’s a bad load?
Correction: voltage divided by resistance.
Normally, yes. BUT I asked you what reading you would get on your meter for the situation discussed in the video where either L1 or L2 are missing. You’re close, you’re almost there!
Would the answer to the question be 0 volts, on my meter?
If either l1 or l2 is missing . You would read 0 volts .
The question only applies,if the heating element is out but the voltage is still present.
Would you be able to disconnect l1 and l2 ,from the heating element . Put the probes on l1 and l2 ( that were just disconnected) and get 240v ?
I believe it would be phase three.
Yes , you’re correct. It’s unit 6.
It’s the last video in the module , for circuit breaker panels & Power outlets.
You showed a handwritten schematic, of l1 and l2 . The picture shows how to half split , to find if there is 120 volts , coming from both lines.This is the video (series /parallel where you ( at the end ) worked out both 100 ohms and the parallel chit together 80 ohms and 480 ohms .
I used my own numbers r1 =84 (series circuit ) and for the parallel circuit A. 83 ohms and B. 423ohms.
I’m able to do your example but it comes out short with my own numbers.I thought it had to be 120v. How far can it be off?
When rounding amperes. Don’t we go up from .5 or greater?
I know one of the answers had .5 ,as the answer. We don’t use quarter or three quarters , for the answer.
Thanks,
John Walters -
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