Keith Robinson

[Keith Robinson]

so my answer after my math is [answer hidden]

[Keith Robinson]

i must be doing my calculations wrong i have 1/ 1/10+ 1/20= 0.03 idk where im going wrong

[Keith Robinson]

thank you sooooo much. this has helped me in ways you couldn’t imagine. Your the best!

[Keith Robinson]

since the main coil is shunted off the answer for the mail coil will be 0v correct?

[Keith Robinson]

its being shunted which means its receiving current just not 120v of current correct each other load is receiving right?

[Keith Robinson]

shunt

[Keith Robinson]

i would say yes

[Keith Robinson]

no their are other paths for electrons can take through the booster and main

[Keith Robinson]

yes the ignitor has to go through the main as well right?

[Keith Robinson]

is the booster and the main coil in a series.

[Keith Robinson]

when i use the zen trick, my left hand goes to L1 and my right goes through the detector switch to the N.

[Keith Robinson]

yes all loads are getting current

[Keith Robinson]

okay so with the voltage drop across the booster and main i came up with a voltage drop of 60v and the ignitor and safety 120v, is that correct?

[Keith Robinson]

okay so with the issue im having is that im not sure im understanding the ‘voltage drop’ in which im not understanding in a series load will use kirschof’s law so if the Ignitor, booster, and safety are all 120vac would the Main coil be 240vac? but if i add them together using kirschofs law the sum comes to 360vac.

[Keith Robinson]

yes the main coil would be 30vac

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