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Michael Louk

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  • in reply to: Module 3 Unit 8 Voltage drop #14019

    3. Does current vary at different points along a series circuit, or will it always be the same?
    A) Current changes with resistance (meaning curent being pushed through R1 is lower than R2).

    4. Based on that answer, how do you calculate current in the circuit?
    A) Current is calculated by I = E/R1 + R2 (E)240/(R)37=(I) 6.48
    B) In question 7 the total current at R2 is 7.5 Amps
    C) 7.5*7.5*32 = 1800 P or watts

    Does this look right?

    I love this stuff!!!!

    in reply to: Module 3 Unit 8 Voltage drop #14017

    Hello Mrs. Brown,

    So… I think I got it. I stayed up way past my bedtime and found some sites that provided me practice. At about midnight it all clicked. The main issue I had was understanding the different formula for Series circuits I=E/R1+R2 verses Parallel circuits 1/1/R1+1/R2 etc.

    Any who,
    Questions 7 & 8
    1. What is the source voltage for this circuit?
    A) This was my first mistake – did not pay attention to the fact this was a 240 VAC
    2. What do you know about the behavior of current in a series circuit?
    A) They all are connected to the same power source. If there is a break in the line (causing an Open circuit) current will not flow.

    PS: Sorry for not labeling this correctly

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