Susan Brown

[Susan Brown]

I chatted about this with the Samurai. The temperature fluctuation you’re talking about (when the temperature deviates from the set temperature by a certain amount) is primarily affected by the controls (sensor, board), although convection fans can smooth that out a bit.

But “fluctuation” could also be referring to hot and cold spots within the oven cell, and that’s more what we are talking about.

So, to make it clearer, we’ll change the wording to something like:

Convection fans even out the temperature distribution in the oven cell, leading to more consistent cooking conditions.

[Susan Brown]

Hi Daniel,

1. Yes, a box or rectangle with various wires connecting to it is usually some kind of board. That is the normal convention, but there are a couple of other clues – there is no wire color label on the lines of that box, and it wouldn’t make sense as part of a circuit – it would be a short circuit.

2. When the fridge needs to go into defrost the board will close a switch from C to D to provide line voltage to the heater.

[Susan Brown]

Hi Juan,

I had posted a quick reply a couple of days ago but, unbeknownst to me, an error occurred and it never actually posted.

We cover the refrigeration system in great detail in our Advanced Refrigerator course, if you eventually decide to take that. But we don’t mind answering some additional questions. These happen to be beyond my ability to answer quickly, so I’ve asked Sam to do that. But he has a training event this week and his time is limited. He will answer when he can!

FYI – I know that you scored 100% on the quiz for this unit. If you were waiting to get help on a specific question so that you could pass the quiz, we would make sure you got an answer ASAP.

• This reply was modified 4 days, 23 hours ago by Susan Brown.

[Susan Brown]

Hi Juan,
I had answered this question a couple of days ago, but just now saw that there was an error and the answer never got posted. Sorry!

1. Circulating air, which evens out the heat distribution, does also help reduce temperature fluctuations.

2. The positive pressure of the gas in the tube combined with the lack of enough air for combustion prevents ignition in the tube.

3. The Igniter is in series with the valve. If you stopped current to the igniter you would also stop it to the valve and the flame would go out. There is not a lot of voltage drop across the igniter once the flame is established, so it doesn’t waste much energy at all.

[Susan Brown]

That is a kit called “Snap Circuits” which is designed for young people to safely experiment with circuits. The blue pieces are just conductors (wires) and the batteries are on a plastic plate with the terminals wired to little metal posts that the blue pieces can snap on to.

[Susan Brown]

Hi Alfredo,
Sure, I just reset that quiz for you.

FYI, when you start a second attempt that message immediately appears – you still are able to take the quiz. But it sounds like something malfunctioned.

Also, it’s always best to use the Quiz & Exam Reset Request form when needed – it is in the Campus Support menu.

Thanks!

[Susan Brown]

Hi Denis,

The symbols for various batteries look like this (in North America – not sure how universal these are).

(Note – the color of the symbols is not important – sometimes they are just in black and white)

So the red lines indicate DC current/voltage from a battery.

Does that answer your question?

• This reply was modified 2 weeks, 6 days ago by Susan Brown.

[Susan Brown]

Hi Julio,

FYI – it would be better to post a new topic in the Forum for the Basic Electricity Module. For some reason this thread is in the Forum for the Tools Module.

Current in a Series Circuit
– is the same throughout the circuit, at every point
– is determined by the total resistance in the circuit

So, for Circuit B, I = E/Rt = 120/100 = 1.2 amps

Voltage Drop
– each load will have a voltage drop that is in proportion to its resistance (Ed = I x R) where R is the resistance of the load in question
– the sum of the voltage drops of loads in series will equal the voltage supply

In the video I calculated the voltage dropped across the 60 ohm load in both circuit A and circuit B to show the effect of having the second load in B.

When the 60 ohm load was the only one in the circuit, it had 120v drop. When it is in series with a 40 ohm load, it has 72v drop.

I didn’t show it, but the 40 ohm load in circuit B has a 48 v drop (E = I x R = 1.2 x 40 = 48v).

72 v + 48v = 120v

Does that help? Let me know!

[Susan Brown]

Hi Julio,

It is not unusual to have to rewatch some of the videos in Module 4 to understand. The first video in Unit 3 I go over using equations like this in general.

I also have a similar discussion/examples here:
https://my.mastersamuraitech.com/appliance-repair-course-support/student-forums/topic/math-and-ohms-law/

And then there’s more in the following units. Take notes, try to reproduce the calculations on your own paper, and let us know if you have questions.

For each unit in Module 4, if there are quiz questions you can’t figure out, let me know and we can use those as examples to help you understand.

It is best to start a new topic in the “Core – Basic Electricity Forum”, FYI, to get help on any of the material in Module 4.

[Susan Brown]

Hi Hayden,

Yes, to earn Certification we require 80% or higher on every unit quiz, and 90% or higher on every exam. See the Orientation, unit 2, for all the details on that.

It looks like you have second attempts available on the Module 4 quizzes. For the Module 2 quiz, we’ll need to work together on that via email. Get in touch when you get a chance! (susan at mastersamuraitech.com)

[Susan Brown]

Since these are “Ask the Teacher” Forums, one of our team members will always respond, and while you may occasionally see another student comment, it is not common. Also, I wanted to point out that you benefit from having over 2000 students having come before you in the Core course. We’ve refined and improved the course over the years whenever it has become obvious that something was needed. We appreciate feedback and welcome questions – I’m sure we’ll always be tweaking things here and there – but also encourage students to trust us and the process! 🙂

• This reply was modified 1 month, 2 weeks ago by Susan Brown.

[Susan Brown]

Always feel free to check on things like this with us as you did via email or here in the Ask the Teacher Forums.

Since the phrase “where the gas condenses into a hot liquid” immediately follows “condenser coils”, we are saying that this change from gas to liquid occurs in the condenser coils. We also reinforce this with one of the quiz questions.

[Susan Brown]

Hi Denis,
Your answer was 350 milliamps – no decimal in front of it. So “three hundred fifty” milliamps, which is equal to 0.350 amps.

[Susan Brown]

Hi Bobby,

The inverter puts out voltage of varying amplitude and frequency depending on the algorithm. It will varying depending on the brand/model. Some manuals will give specs for this, some don’t. We don’t usually measure voltage on these lines.

[Susan Brown]

Im looking at the diagram and assuming the questions are asking what happens when the diode fails causing an open circuit in the branch convection element. so there would be current flow till the diode fails.

Yes – so the current stops (decreases) in the element circuit.

The voltage drop wouldn’t change because the voltage applied is the same to both branches. The current in fan motor branch will go unchanged it will be the voltage divided by the resistance of the fan motor.

Correct. It’s also easy to just think of it as: the failure in one circuit has no effect on any circuits that are in parallel with it.

This will cause a higher resistance in the circuit makeing a lower current draw.

Yes. You can also think of it in terms of total current. Total current for parallel circuits is the sum of the current in each circuit. So if one decreases and the other stays the same, the total decreases.

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