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Hi Juan – I’ll shoot you an email about this right now.
Yes, same thing. Assuming the neutral is properly grounded (and the person), there could be a million volts on the Line side and it wouldn’t change things.
The assignments in the book are a supplement – helpful, but not the main part of the instruction. Being able to read them on the pdf version is fine.
Correct. Which means there is no voltage to cause electrons to move (current flow) in your body.
Does that help?
Remember that to have electron movement (current), you must have a complete circuit and voltage applied to that circuit (meaning: a difference in charge between two points).
If you are standing on the ground, and touch a neutral wire, what is the difference in charge (voltage) between you and the neutral wire?
December 15, 2024 at 10:30 am in reply to: Module 4, Unit 8: Voltage, Voltage Drop, and Loads #268111 is correct
7: your answer was “About 1,350 heat units”
“Heat units” is not a valid way to express heat. It is “watts” (1350 is the correct numerical answer)10: You are closer. Yes, this is a 240v circuit. But remember that the voltage drop of R1 will be two times that of R2. Your answers of 80v for R1 and 160v for R2 is the opposite of that.
Hi Carl,
FYI, this is the Unit 5 quiz (I edited the title of this topic).
#5: The two circuits shown in the diagram are L1-N1 and L2-N2. They are both 120v circuits. Since we told you the input (L1-N1) was verified, the next step would be testing output (L2-N2). 120v is what we would expect to read.
#7: See Unit 4, the section titled “Load Analysis (identifying the power supply for your Load of Interest)”
#17: Did you see the explanation that shows up in the results of the quiz?
The heating element should be getting 120 V AC at each terminal. The fact that one side is not giving voltage means that something is open on that side. In this case, one of the controls are stuck open.
Hi Ronny,
Quick reminder that exams must be 90% or higher for Certification. Take a look at your Module 1 Exam score. (You have a second attempt available)
The answer is “Freezer evaporator”. The first video in the unit shows how the fresh-food evaporator is in series with the freezer, but can also be bypassed. So, the freezer is always getting refrigerant.
Video tip: did you know that there are transcripts that you can scan through or search? (It’s the symbol in the bottom frame of the video, between “CC” and the gear.) That’s a handy tool when you are reviewing for tests.
That is correct, good job! (I will hide the answers so we don’t give it away to others)
Hi Jozsef,
Please look for an email I just sent to you!Hi Chris,
Did you try this link? Should open the pdf for you, without needing you to join or get other access. If you get a pop-up window inviting you to set up something with Proton, just click the “x” to make it go away, then it should pull up the pdf. I just did that using the Chrome browser as an anonymous guest, so Proton couldn’t recognize me from previous interactions.
https://drive.proton.me/urls/59YNZQYB88#MrYvJmlY1GLc
Let me know if that works.Did you mean its not a motor its a valve that flushes the dispenser so it would be none for my answer?
That’s correct!
Yes, that is.
So it looks like I calculate only the resistance of R2 when finding power
Yes – because we only wanted to know the heat generated by the load “R2” which has 40 ohms of resistance.
Current flow (the rate of electron movement) is determined by the total resistance in the circuit. It is not different at different points – it is the same at every point in the circuit.
But voltage drop and power will be different over different loads in series (unless the loads all have identical resistances)
Yes, that is correct.
In a series circuit, the current is the same throughout the circuit – at any point you’ll measure the same amps. It is determined by the voltage (total dropped across the loads, which will be the same as the voltage supply) and the total resistance. So, 2 amps is correct.
Now, you know the current flowing through R2. You know the resistance of R2. Choose the right formula for P and you should get the right value for the heat (watts) generated by R2.
Hi Leigh Anne,
The quiz question asks what the minimum temperature is
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