Susan Brown

[Susan Brown]

Wondering what the answer list for question 6 was…. i got it wrong, but i think i know why now.

23 ohms
10 amps
10 ohms

also i got question 8 correct, but if you could help explain a little more ……
In the context of voltage drop in a circuit, current is ___ proportional to voltage.

directly proportional because E = I X R ……………. voltage drop would be the E ….. current would be the I…. but i dont understand how resistance gets involved to make it directly proportional

Resistance is also directly proportional to voltage drop.

Generally speaking, when we say this, we mean that we are assuming no change in the other variables. So, assuming no change in R, when we increase I, E will also increase. Or, assuming no change in I, when R is higher, E will be higher.

For example, if you have a 5 ohm load, and you put 5 amps through it, the voltage drop will be 25 volts. If you have a 5 ohm load and you put 10 amps through it, you will have a 50 volt drop across it. Higher current = higher voltage drop.

Or, we could say we have current of 10 amps, and say that if we have a 5 ohm load, the voltage drop is 50 volts. Then if we have 10 amps going through a 10 ohm load, then the voltage drop would be 100 volts. Higher resistance = higher voltage drop

This is the math that describes the basic relationships between these properties. You will see as the lessons continue that you have to also take into account how circuits behave in real life. For example, in circuits, the resistance of the components in the circuit and the voltage supply (120v or 240v) will determine what the current is. We’ll step you through this info in the coming units!

[Susan Brown]

I thought an open would mean no current could flow?

Correct! So: current was flowing before the failure, and then it stopped when the diode failed open, then that is a decrease.

[Susan Brown]

Sometimes getting an answer wrong at first is the best way to eventually learn! It’s all part of the process. 🙂

[Susan Brown]

Hi Juan – no, they are either open or closed. It is the timing of how long each one is open that determines the temperature.

[Susan Brown]

Hi Cory,

“How long this valve is kept energized depends on the model, but it is usually under 2 minutes to get the specified amount of water in the tub.”

So the answer choice that is best is “Probably, but it depends on the model”

[Susan Brown]

Did you receive the email I sent you so we could work on this together?

[Susan Brown]

Hi Matthew,
That black bar is the defrost heater.

[Susan Brown]

These Forums are a different plug-in at the website than the quiz software, so it must be something that has changed just with this plugin. Thanks so much for letting us know about it!

[Susan Brown]

The detector switch *is* a shunt that bypasses one of the loads, but not all.

[Susan Brown]

reply 3

[Susan Brown]

reply

[Susan Brown]

Hi Cory,

FYI – this is in Unit 5.

The two resistances that are in parallel are 80 ohms and 480 ohms.

The formula is Req = 1/(1/R1 + 1/R2)

Req = 1/(1/80 + 1/480)

Turn 1/80 and 1/480 into decimal numbers using your calculator.
“1 divided by 80” = 0.0125
“1 divided by 480” = 0.002

Req = 1/(0.0125 + 0.002) = 1/(0.0145) = 69

Let me know if you need any further help!

[Susan Brown]

1. They use a combination of sensors and computer control to open and close the hot and cold valves to achieve the desired temperature.

2. Yes – you can see that it is on the exterior of the washer so that it is easy for the homeowner to remove and clean.

[Susan Brown]

Also, in other news, I am not getting any emails letting me know I got a reply in this forum. I made sure my email was set correctly on my profile, made sure the checkmark below the comment box was marked to get them, and I checked my spam and trash folder, and searched everywhere. Definitely not getting them. Any help?

Sorry to hear that! I’ll let our IT guy know so he can look into this.

[Susan Brown]

Hi John,

I moved this to a new topic, FYI.

I’ll ask you a few questions to help step you through this.

1. If you have a circuit with one load in it that has direct access to Line and Neutral, what will the voltage drop be across that load?

2. What is a shunt? (See Unit 1 definitions and Unit 5, first video)

3. How are the Ignitor, Booster, and Safety situated relative to each other? (series or parallel)

4. What impact does the closed detector switch have on the circuits?

Let me know what you think the answers are to those four questions.

[Author]

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