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Yes, 2, 3, and 4 are the same series circuit with 3 loads, and we give you the resistances.
Question 2 asks for the total resistance.
You know each individual resistance – how do you find the total? (The word “total” is a big hint.)
Answer that, then we’ll move on to the next question.
May 30, 2019 at 4:48 pm in reply to: How to find voltage drop if I don't know resistance of loads #15932Hi Steve,
Since you are asking about different types of calculations, and some of them are unrelated to this original post, I’m going to move your question to a new topic.
Steve – See the video in this topic: https://my.mastersamuraitech.com/appliance-repair-course-support/student-forums/topic/calculating-equivalent-resistance/
Hello – no, the Final Exam does not include questions from the bonus modules.
Hi Tom,
We don’t have that available, but you can always take a screen shot of any of the slides that you’d like to have on hand.
Hi Tom,
Normally, it would mean rolling it away from the wall so you can reach the back. But, just to make sure I’m giving you the correct answer, where did you see that in the course?
Done!
Great! I’m glad you asked the question. Thank you!
Do you want me to reset that quiz so you can retake it?
Yes, P2-6 is a good test point for the L2 side of the element.
From the component ratings on the tech sheet, we would expect around 16 ohms resistance if the element is NOT open.
It sounds like you are trying to find two test points that are EEPs with each other, but that is not what we’re trying to do with EEPs. Each convenient testing point needs to be an EEP with one of the power supply lines to the LOI.
The two sides of the element are not EEPs. Any two points that have a load in between them are not electrically equivalent.
Do you remember the two criteria for EEPs?
Two points that
1. are in continuity with each other, and
2. have no voltage difference between them.You are basically looking for a wire that connects to the load of interest, with no other loads along the way.
You need to put your meter probes in two locations to measure the resistance. You are looking for two test points that will be electrically equivalent to either side of the element. (same thing if this happened to be a voltage measurement)
For example, you are correct that P1-1 is a good test point. A wire connects directly from P1-1 to one side of the element. P1-1 is an EEP for the L1 side of the element.
Now you need an EEP for the L2 side of the element.
Hi Travis,
You’ve already indicated in your previous answers on the quizzes that you are trying to measure resistance (ohms) of the load of interest – the upper bake element.
Your current answer on the unit 7 quiz is to use the test points P1-1 to P1-6. Looking at the diagram on the tech sheet, does that isolate the bake element?
In the schematic the switch is closed so it changes the direction of the current right?
“Changes direction” isn’t the best way to think of it (it could get confused with the way that AC current changes directions), but you are getting at the right idea. The switch being closed creates a certain condition that affects the voltage drop of the loads.
It sounds like you are guessing. You’ve gone from saying none of them get current, now two of them get current. Which two do, and which two don’t, and why?
What makes you say they aren’t receiving current? The problem states that you have a good 120 VAC power supply.
Jake – did you read what I wrote above? I moved your question to its own topic. This thread is on equivalent resistance of parallel circuits.
Here’s the link, but you can also just find it by looking at the list of topics in the Basic Electricity Forum.
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