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Hi Luke,
Good question!
This may be a 120/208v commercial system. You see this a lot in apartment buildings (you can do an internet search for 208 voltage supply to read more about this). If that’s the case, then your readings are to be expected.
A reminder – we always recommend you do measurements with respect to Neutral, not Ground. They should be the same potential, but that’s making an assumption that you may not know for sure.
Hi Luke – let us know if you have any other questions. This is a great topic to make sure you understand. Also, I sent you an email earlier today about your Certification. Please look for it! (If you don’t see it in your inbox, check your spam folder.)
You aren’t the first one to get tripped up on this one! 🙂
Hi Samuel,
Good question. I’m glad you’re trying to really nail this down.
If we are talking AC current, then there isn’t technically a “first” load, since the current changes directions.
All the loads in the series circuit will affect what the circuit current is. In fact, you can just add the resistances of the loads together to get the total resistance for the circuit, and knowing that and the source voltage, you can calculate the current of that circuit.
The source voltage gets dropped across each load in proportion to the resistance of the load. If you had two identical loads in a circuit, then each would drop half of the voltage. If one load was twice as high as the other, then it would drop twice the amount of voltage as the other. But once you have calculated the current going through the circuit (which is the same throughout a series circuit), then you can also just calculate the voltage drop across each load with E = I x R.
Does that help? Let me know if you have any followup questions.
Hi Abe,
I’m glad you brought this to my attention. The correct answer is supposed to be “all of the above” – and that used to be one of the options. Somehow that had gotten altered – I’ve fixed it now.
Thanks!
SusanHi Dan,
You are correct that voltage and current are both required for a load to do work. And the combination of voltage and current is also known as “power”. (P = I x E)
That’s the answer we are looking for there.
So it has to do with the sealed system, correct?
Do you see where in the video he’s talking about seeing the ice ball? What type of failure is being described there?
Just want to make sure – Did you notice the word “not” in the question?
Hi Jim – thanks for the question! I’m going to have to consult with Mr. Samurai on this one, and he is out for the whole day. As soon as I have an answer for you I’ll get back to you.
We talk about the ice ball about halfway through the video in that unit.
Look at the photo in Unit 2 of several different evap frost patterns. Which one matches the description?
just did
That’s a correct statement. The answer choices we give you for that question aren’t quite so detailed, but I think you’ll know which one is correct.
Right! So, you can only assume there will be some kind of start device, but not which type. The correct answer has to do with the type of windings that all split-phase motors will have.
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