Susan Brown

[Susan Brown]

Oops – we were posting at the same time. I said you were correct about the fuse not dropping voltage – and that’s what we ask in the question.

The load in the circuit (the bulb) will drop the voltage. Make sense?

[Susan Brown]

Correct! So that’s your answer.

We threw a lot of info at you in this question (which is similar to what happens on a service call), but you just need to think about that one fact – a fuse is basically a switch and thus won’t drop any voltage.

[Susan Brown]

Correct! And do switches drop voltage?

[Susan Brown]

Hi Matt,

First ask yourself a question: is a fuse a load? Remember, pretty much any component in a circuit is either a switch or a load. What is a fuse?

[Susan Brown]

Hi Bryan,

The material we put in our courses is what we know, from many years of experience, to be the foundational information and skills that a capable appliance tech needs to have. In order to be able to troubleshoot electrical systems, you not only have to be able to read a schematic and devise a testing strategy, then you have to interpret the measurements you get – which can sometimes be tricky.

To do this well, you have to have a really good feel for basic circuits and electricity. Ohms Law simply describes how the electrical properties that you need to understand relate to each other. So that’s the main way it’s useful to an appliance tech – to first learn about electricity, then to have something to use when needed to interpret the various measurements you’re taking with your meter(s). There’s no other way to have a solid, functional understanding of how electricity works.

So, its initial usefulness is as an important part of the learning process. An experienced tech who has a good understanding of circuits and electricity will no longer have to do a lot of actual calculations using Ohm’s Law equations, but they still can come in handy now and then when you encounter an unusual head-scratcher type of a scenario.

Hope that helps!

[Susan Brown]

Ah – that is something we picked up at a manufacturer’s training. From Miele, if my memory serves. I don’t know how to obtain one. Are you Miele authorized?

[Susan Brown]

I’m glad you love this stuff! And you are getting close.

This is great because we have identified one area of misunderstanding you have about current in a series circuit.

If you need to, go back and review a little bit of our instruction about current – how electrons flow. In a circuit, if one electron is moving, they are all moving. And all at the same rate. Picture a line of billiard balls that are all touching each other, with no extra space anywhere. If you push the one on the end, they will all move at the same rate. If you stop the one on the front end, they all stop. Electrons behave in that kind of way. What that rate (current flow) is will be determined by the total resistance of the circuit, not by the individual load they are going through at a particular moment in time.

Again – this is for loads in series, not parallel.

Look at the equation you gave in 4.A. I = E / (R1+R2). You are saying there that the current is the voltage divided by the total resistance. That math equation is showing what I said above, basically.

So the circuit current is 6.48 amps, at both R1 AND R2.

Let me know if that makes sense to you.

[Susan Brown]

Good to hear back from you!

Good answers so far.

3. Does current vary at different points along a series circuit, or will it always be the same?

4. Based on that answer, how do you calculate current in the circuit?

[Susan Brown]

Hi Mike,

Glad to help!

(Note that I changed the title of your topic to the unit where you scored a 70%.)

This is THE most common unit in this module for students to struggle with, so don’t feel bad.

First of all, look at Question 6. The thing that is wrong about the answer you chose is not the number. We were asking for the reading on an ammeter (also sometimes called an amp-meter). Does that mean we were looking for voltage or current?

Then for 7 and 8, we’ve got two loads in a series. I’m going to step you through this a bit with questions.

1. What is the source voltage for this circuit?
2. What do you know about the behavior of current in a series circuit?

Answer those and then we’ll continue on.

[Susan Brown]

Hi David,

It’s been awhile since I’ve watched those videos – I’m assuming this is something mentioned there. Are you talking about the tool for Miele dishwashers?

[Susan Brown]

Hi there – sorry about that. The recording is available to you here:

https://mastersamuraitech.com/webinar-recording-basic-refrigerator-troubleshooting/

[Susan Brown]

Hi Phil,

Here’s what I do. After I’ve watched it through once, I restart the video and pause at each slide to take notes. You can click ahead in the progress bar to advance to the next slide(s) without actually having to listen to all of it again, unless there are parts you didn’t quite catch the first time.

Hope that helps!

[Susan Brown]

That is correct! The one branch has a failure, of course, and current will stop in that one, which decreases the overall current draw. But the branch parallel to it will be unaffected.

[Susan Brown]

Yes, that’s correct. (I’m going to hide your answer, by the way.)

The equivalent resistance will always be less than the smallest resistance of the individual loads.

[Susan Brown]

Here it is embedded for you:

https://www.youtube.com/embed/iHB3lxdc68E

 

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