Susan Brown

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  • in reply to: Module 3 unit 2 and doing quizzes while exhausted #14344
    Susan Brown
    Keymaster

      Note that the questions don’t tell you the voltage drop – they are asking you to determine the voltage drop. They tell you the lines of voltage that are applied to either side of the load.

      Remember voltage drop is created by current flowing through a load.

      And current will only flow in a circuit where there is a difference in voltage applied to either end.

      in reply to: Module 11, unit 4 #14339
      Susan Brown
      Keymaster

        Ah! You are looking at the wrong light on the schematic. The “surf ind light” just goes on when any surface element is turned on. The hot surface indicator lights are different. There are 4 of them, and they are switched by a thermostat and come on if the glass temp is >150 deg.

        I’m not sure how you got the other questions correct on these quizzes. You should be looking at the LF “hot ind light” (there are 4 of those lights)

        in reply to: Module 11, unit 4 #14337
        Susan Brown
        Keymaster

          Let’s make sure we are looking at the correct light on the schematic. How is the light that you are looking at labeled?

          in reply to: Module 9, unit 1 #14334
          Susan Brown
          Keymaster

            Right, and to get a little more specific, the statement said that the customer set the oven to low bake. A valid problem statement could be “oven won’t heat on bake”, but we gave slightly more specific choices in the question for this Case Study.

            in reply to: Module 9, unit 1 #14332
            Susan Brown
            Keymaster

              Based on what the customer set the range to do, and the results the next morning, what is the range not doing that it should be doing?

              in reply to: unit 6 #14290
              Susan Brown
              Keymaster

                The question is asking for the equivalent resistance of two loads that are shown in the diagram.

                1. What relationship are those loads in? (series or parallel?)

                2. Based on the answer to that question, what is the rule of thumb for the equivalent resistance of loads in that configuration? (We give that in the 3rd video in that unit)

                in reply to: question 31 #14287
                Susan Brown
                Keymaster

                  That is the explanation we give as a help for those having a hard time with that question. I’m not sure what your particular question is. These are the same steps that you took to get the answer for Question 6 on the Midterm Exam. We also show a similar calculation in the last video in unit 3 of Basic Electricity.

                  Is there a specific question you have about this?

                  in reply to: loads #14194
                  Susan Brown
                  Keymaster

                    Another important characteristic of a load is that when current flows through it, a voltage drop is created.

                    in reply to: 1.3: Fundamentals – Basic Electricity Fund exam Q's #14187
                    Susan Brown
                    Keymaster

                      I assume you are talking about this question:

                      If the Defrost Heater and the Freezer Drain Heater are operating within specifications, what equivalent resistance would you measure from Pin 13 to Pin 7 in the diagram below:

                      Here’s your answer:
                      58 Ω because the equivalent resistance in a parallel circuit will always be equal to the smallest branch resistance.

                      The heaters are in parallel, with resistances of 58ohms and 320ohms.

                      Is that the correct rule of thumb for equivalent resistance of parallel loads?

                      in reply to: Module 3, Unit 8, question #7 #14184
                      Susan Brown
                      Keymaster

                        Correct! I’m glad to see that you are making sure that you understand all of the questions and answers.

                        in reply to: Module 3, Unit 8, question #7 #14182
                        Susan Brown
                        Keymaster

                          Hi John,

                          You’ve got the correct quantity (“about 1350”), but what are “heat units”? That’s not a normal way for us to quantify heat (and thus not the correct answer).

                          There was another choice for an answer that uses the correct units – do you know what that would be?

                          in reply to: 1.3 Fundamentals- Basic Electricity Exam Q's #14178
                          Susan Brown
                          Keymaster

                            The concept of this problem is very similar to the “loose connection” problem that you successfully calculated on the Midterm Exam (Question 6). Two loads in series, and calculating the heat produced by one of the loads in particular. Look back over your answer for that and let me know if you still understand what you did there.

                            in reply to: 1.3 Fundamentals- Basic Electricity Exam Q's #14176
                            Susan Brown
                            Keymaster

                              Hi Phillip,

                              Are you talking about this question?

                              You’re working on an appliance with the circuit configuration shown below. R1 = 5 ohms. R2 = 32 ohms. If everything is working correctly, what is the expected heat produced by R2?

                              Susan Brown
                              Keymaster

                                Hi Phillip,

                                See if this video helps: https://youtu.be/cLkeBsDXjZc

                                For any more detailed advice on service calls, please use Appliantology.org.

                                in reply to: Module 3 Unit 8 Voltage drop #14171
                                Susan Brown
                                Keymaster

                                  Great!

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