Susan Brown

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  • in reply to: Question #3: #14366
    Susan Brown
    Keymaster

      Correct – so would any current be flowing?

      in reply to: unit 5 quiz question #16 #14362
      Susan Brown
      Keymaster

        Sure – but I was hoping you would give me the answer – the name of the situation I am talking about – so I can make sure you got it.

        in reply to: unit 5 quiz question #8 #14359
        Susan Brown
        Keymaster

          It’s a good idea to take the time to get these circuit configurations straight in your mind.

          The videos at the end of Unit 4 are good to review for this.

          Also, do you understand the “Zen trick” we teach in the second video in Unit 5?

          in reply to: Question #4: #14358
          Susan Brown
          Keymaster

            When you figure out the answer to Question 3, I think you’ll see what this answer is.

            in reply to: Question #3: #14357
            Susan Brown
            Keymaster

              These light bulbs are in series.

              In a circuit, you must have a complete path to and from the power supply for current to flow. (If we’re talking about a 120vac circuit, then we need an unbroken path from L1 to N.)

              Since the bulbs are in series, there is no alternate path for current to flow. The electrons have to be able to go through both of them in order to have current flow.

              What happens to the circuit when a light bulb blows?

              in reply to: Question #6 quiz #14356
              Susan Brown
              Keymaster

                Voltage drop is directly proportional to the resistance of a load. In other words, higher resistance equals higher voltage drop.

                If you had two or more loads in series, the only way their voltage drop would be identical is if they had the exact same resistance.

                in reply to: unit 5 quiz question #16 #14355
                Susan Brown
                Keymaster

                  Hi Ladarius,

                  Thanks for posting your questions in the Forums!

                  It is not a small difference for that switch to be closed – it affects the circuit quite a bit.

                  What the branch does to the circuit when the switch is closed is discussed in the 3rd video in Unit 5. It is a particular circuit design to control loads (either give them power or divert it).

                  Do you know what I’m referring to?

                  in reply to: Module 3 unit 2 and doing quizzes while exhausted #14344
                  Susan Brown
                  Keymaster

                    Note that the questions don’t tell you the voltage drop – they are asking you to determine the voltage drop. They tell you the lines of voltage that are applied to either side of the load.

                    Remember voltage drop is created by current flowing through a load.

                    And current will only flow in a circuit where there is a difference in voltage applied to either end.

                    in reply to: Module 11, unit 4 #14339
                    Susan Brown
                    Keymaster

                      Ah! You are looking at the wrong light on the schematic. The “surf ind light” just goes on when any surface element is turned on. The hot surface indicator lights are different. There are 4 of them, and they are switched by a thermostat and come on if the glass temp is >150 deg.

                      I’m not sure how you got the other questions correct on these quizzes. You should be looking at the LF “hot ind light” (there are 4 of those lights)

                      in reply to: Module 11, unit 4 #14337
                      Susan Brown
                      Keymaster

                        Let’s make sure we are looking at the correct light on the schematic. How is the light that you are looking at labeled?

                        in reply to: Module 9, unit 1 #14334
                        Susan Brown
                        Keymaster

                          Right, and to get a little more specific, the statement said that the customer set the oven to low bake. A valid problem statement could be “oven won’t heat on bake”, but we gave slightly more specific choices in the question for this Case Study.

                          in reply to: Module 9, unit 1 #14332
                          Susan Brown
                          Keymaster

                            Based on what the customer set the range to do, and the results the next morning, what is the range not doing that it should be doing?

                            in reply to: unit 6 #14290
                            Susan Brown
                            Keymaster

                              The question is asking for the equivalent resistance of two loads that are shown in the diagram.

                              1. What relationship are those loads in? (series or parallel?)

                              2. Based on the answer to that question, what is the rule of thumb for the equivalent resistance of loads in that configuration? (We give that in the 3rd video in that unit)

                              in reply to: question 31 #14287
                              Susan Brown
                              Keymaster

                                That is the explanation we give as a help for those having a hard time with that question. I’m not sure what your particular question is. These are the same steps that you took to get the answer for Question 6 on the Midterm Exam. We also show a similar calculation in the last video in unit 3 of Basic Electricity.

                                Is there a specific question you have about this?

                                in reply to: loads #14194
                                Susan Brown
                                Keymaster

                                  Another important characteristic of a load is that when current flows through it, a voltage drop is created.

                                Viewing 15 posts - 1,726 through 1,740 (of 2,011 total)