Forum Replies Created
-
AuthorPosts
-
Hi Chip,
Happy to help!
First of all, do you remember how to calculate (or what the rule of thumb is) for the equivalent resistance of loads in parallel? You covered this in Fundamentals.
Yay! Exactly correct on all accounts. (Note: I’m going to hide your answers)
Just to summarize:
The general term “voltage” is the difference in electrical charge between two points.
When current is flowing through a load, there will be a difference in voltage between one side of the load and the other. This is “voltage drop”. And yes, loads in series will behave according to Kirchoff’s law.
Measuring a voltage across an open switch (or a load that has failed open) is NOT voltage drop, because there is no current flowing.
I’m glad that you are working on understanding this!
The short answer is “voltage drop is created by current flowing through a load”
Let’s unpack that just a bit.
How would you define “voltage” in your own words? (Just the word “voltage” – not necessarily voltage drop.)
Hi Josh,
Let’s talk about Question 9 first. I hid the last part of your answer, so we wouldn’t give it away to other students who haven’t taken it yet. But that is correct.
Another thing to think about with the measurements shown in Figure 1 is – what does it mean if you know that the element is good, but there is zero voltage drop across it? What creates a voltage drop? We are measuring some voltage, but what is missing?
Question 8: Please read through this topic and see if it helps. Be sure to read the whole thread, as several students chime in with questions. If not, ask another followup question.
Awesome! That’s what I like to hear 🙂
If you are the booster, is there not a way to get to N without going through the main coil? (twists and turns don’t matter to an electron: wire is wire)
Hi Sam,
This can be a tricky one! But you’ll get it. Let’s try this:
For each load, try the Zen trick that we describe in Unit 5. If you can become that load and reach L1 and N without going through another load, then you will drop 120vac, correct?
Are there any loads that you think you can’t reach L1 and N without going through another load? If so, which one(s)?
Hi Shannon,
I take it that you need a reset on the quiz and are offering these as correct answers for what you missed?
I’m always glad when someone posts a topic here to get additional help, but we want you to ask general questions like, “I’m having a hard time finding out what the brushes in an AC induction motor are made of” rather than posting Q & A’s here. For one thing, I have to then hide the answers so other students can’t copy them.
Please keep that in mind for the future.
Also, we have a new way of requesting a reset. See this page: https://my.mastersamuraitech.com/quiz-exam-reset-request/
I’m hiding your answers, but I can tell you that you are correct for #13 and #14. Not for #3. (Do AC motors have brushes?)
Hi Andranik,
Thanks for posting in the Forums, although if you are asking a new question, it’s best to start a new topic. I’ve moved your post to a new topic.
You didn’t ask a question above, but I’m assuming you got this wrong on a quiz? Look back over the definitions in Unit 1 and see if you see one that talks about “potential”, and let me know what you think.
Hi John,
Are you on a PC or a Mac computer? I know that on my Mac I can hit Command and the + sign to zoom in.
August 5, 2017 at 3:32 pm in reply to: Question about current and voltage in parallel circuits #13088Hi Kokomo,
Samurai talked about series loads, but Boyd’s post is about parallel loads. Is that what you were talking about?
If so, that’s a different scenario.
What is the fact about voltage in parallel circuits? Does it divide up among the branches, or does each branch get the full supply voltage?
Since the question didn’t specify that a loading meter was used, then that does raise uncertainty about the voltage reading. Also, reading voltage alone doesn’t tell you that current is flowing. And loads need power (both voltage and current) to operate.
Does that make sense?
It’s one opening true-false question, then 8 open-answer questions. It’s very Ohm’s Law and basic circuits-oriented, so there are various simple circuit drawings you’ll be looking at.
Not gonna lie – it’s a challenge! More often than not students need a second attempt to pass. BUT – it provides some great learning moments along the way. We found that we need to stretch students at this point to help some of the concepts really sink in.
Don’t stress about it, though. Study the topics we suggest, make sure you’ve got a solid understanding of all the quiz questions and answers, and then go for it. One way or the other it will just be part of the learning process, whether you pass it in the first attempt or the second.
Good question!
Our estimate would be about $700-$1000.
Correct! Any more questions about this topic? If not, you can retake the quiz now.
-
AuthorPosts
