Susan Brown

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Viewing 15 posts - 466 through 480 (of 2,002 total)
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  • Susan Brown
    Keymaster

      You got it!

      in reply to: Module 4 – Unit 6: Question 10 #24109
      Susan Brown
      Keymaster

        Sure – we haven’t had any other students ask about that one, but it doesn’t hurt to dial in questions a bit. Glad you enjoyed the course!

        in reply to: Midterm question 4 #24107
        Susan Brown
        Keymaster

          Hi Lukas,

          Assuming you are using the correct equation for voltage drop, yes – you will use the current from Question 3 as part of that calculation for each load.

          in reply to: Module 4 – Unit 6: Question 10 #24105
          Susan Brown
          Keymaster

            Hi Adam,

            Scott makes a distinction between the valves (primary/main and secondary) and the regulator. I don’t believe he calls the regulator a “valve” in that first video.

            I think we’ll tweak the wording on the question to make it a bit clearer, and ask how many *solenoid* valves, rather than *physical*.

            Hopefully this has made it clear that the answer is 2.

            in reply to: Module 4 – Unit 4: question 13 #24103
            Susan Brown
            Keymaster

              Hi Adam,

              P/E is how you calculate I, not R. So 2560w/240v = 11 amps. You could then go on to do R = E/I = 22 ohms.

              Or you could just do one calculation with R = E^2/P which also gives you 22 ohms.

              in reply to: Quiz questions 7 & 8 #24097
              Susan Brown
              Keymaster

                That is the formula we recommend.

                To get the correct answer with that formula, you have to have the correct values for I (current) and R.

                How do you find the current in a circuit with multiple loads in series?

                in reply to: Module 4 – Unit 2: third video down GE dryer no run #24096
                Susan Brown
                Keymaster

                  Yes, that is all that was wrong, and yes, fuses can just go bad. In fact, Samurai had a short follow-up rant about that in this video:

                  https://youtu.be/Pxye3KIodaM

                  in reply to: Module 3 – Unit 4: Question 1 #24093
                  Susan Brown
                  Keymaster

                    Thanks – that was helpful.

                    The 5vdc is acting as data: is the door locked or unlocked?

                    The 12vdc is the operating voltage that is doing the locking or unlocking.

                    • This reply was modified 2 years, 10 months ago by Susan Brown.
                    in reply to: Series vs parallel current flow #24086
                    Susan Brown
                    Keymaster

                      One key point to keep in mind is that parallel circuits (note the plural of “circuits”) are individual circuits that happen to be tied to the same power supply.

                      In any one of those individual circuits, the current is determined by the total resistance in the circuit and the supply voltage. (I = E/R)

                      So if all you have is one circuit, like we go over in Unit 4, you are just dealing with one current.

                      Then with parallel circuits, you have two or more circuits tied together, and can have a different current in each circuit, assuming that there is a different resistance in each circuit. The total current (in and out of the parallel portion) will be the sum of those currents.

                      It just takes time, review, and playing around with scenarios on paper to really get this stuff to click. Just keep at it, and feel free to ask more questions!

                      in reply to: Module 3 – Unit 4: Question 1 #24083
                      Susan Brown
                      Keymaster

                        Hi Adam,

                        Not a trick question. If you look at the first video in the unit, there are two operating voltages that are represented in the various examples that he showed: 120vac and 12vdc.

                        It’s been awhile since I watched it, so I don’t remember where the 5vdc shows up. But 5vdc is usually for a communications line of some sort. Do you happen to know where in the video that is shown or mentioned?

                        in reply to: core refrigerator overview #24078
                        Susan Brown
                        Keymaster

                          We always listen to everyone’s opinion, and take them into account, and make any updates or improvements that seem to be the best fit for the most people. There are a lot of different opinions, as you can imagine.

                          While it is a fairly long quiz, every question on it can be answered by watching the 6-minute video that we include and either repeating the information back to us or just logically applying it to a simple problem scenario. If you think there are particular questions that are not able to be answered just by watching that video, let me know. Most of our students get a good score by their second attempt, so I haven’t seen a pattern of this being particularly difficult.

                          Thanks for sharing your opinion with us!

                          in reply to: Module 2 – Unit 4: Questions 9 & 14 #24074
                          Susan Brown
                          Keymaster

                            Question 9:
                            Of your answers, these two are correct:
                            How to enter diagnostic mode
                            How to read/interpret error codes

                            “Step-by-step troubleshooting instructions” is not. (That’s not to say there won’t be any troubleshooting help, but the tech is expected to provide his/her troubleshooting expertise and the tech sheet will provide all the specifications needed.)

                            The third answer is “the schematic.”

                            Question 14:
                            A sine wave (your answer) is a smooth wave that alternates between the positive and negative. AC current can be depicted this way. Digital signals are square wave DC voltage pulses that do not go negative. (We go over these items in more detail in the Core course.) Typically, digital signals alternate between 0vdc and 5vdc.

                            in reply to: core refrigerator overview #24072
                            Susan Brown
                            Keymaster

                              Hi Max,

                              You are taking the Core Appliance Repair Training course, and that unit was just an “Operational Overview” of the systems in a refrigerator. All of the quiz questions are based on the information in the video. (We’ve had hundreds of students pass that quiz, so we know that it can be done!)

                              The Operational Overview module is to make sure everyone has a very basic knowledge of how each appliance works before diving into the Basic electricity, circuits, troubleshooting, etc. material.

                              We have a whole separate course on Advanced Refrigerator Repair for anyone who wants deeper instruction on refrigerators.

                              I’m sorry that you are disappointed. Most of our students appreciate these overviews, but not all people are the same.

                              If you decide that the course is not right for you, you can request a refund within 3 days of enrolling.

                              in reply to: Module 4 Unit 6 Half Splitting #24069
                              Susan Brown
                              Keymaster

                                We just show that for the sake of completeness and comparison, to see what has changed since disconnecting L1.

                                Even if there were no other fault in the circuit, the act of disconnecting L1 would result in no voltage drop across the element.

                                in reply to: Parallel and Series-Parallel Circuits #24064
                                Susan Brown
                                Keymaster

                                  That is correct, as long as we are talking about a set of parallel circuits, NOT series-parallel.

                                  Parallel circuits each have access to the full source voltage. That doesn’t change if one of the circuits fails.

                                  I = E/R

                                  E and R don’t change for the non-failed circuits, so I won’t change.

                                  Does that help?

                                Viewing 15 posts - 466 through 480 (of 2,002 total)