Forum Replies Created
-
AuthorPosts
-
Hi Clifford,
I’m happy to help. Is it doing the actual “1 over…” calculation that you are having trouble with and getting the same answers we do?
If so, I suggest you rewatch the last section of the video in Unit 3, where I go over some basic math.
And then, in the second video of Unit 5, starting a bit before the 6 minute mark, I explain equivalent resistance and show the calculation. Let me know which part of that you have difficulty following, and I’ll break it down further for you.
Hi Adam,
You were close. The answers are:
They must be in continuity with each other
There must not be any voltage difference between themIt’s been awhile since we just used the hard copy. I know that we bought an updated version at some point, then switched to online. You can ask them typically how long the print version stays relevant.
They aren’t cheap, but very useful. We used this one: https://appliancebluebook.com/
In the old days, we got a paper copy. Then we switched to the online version.
Hi Jason – please send me an email requesting it, then I’ll forward that to the person who sets those up for us. Either use the Contact form at the site, or susan at mastersamuraitech.com
No, it would be a company that primarily sells wholesale to service companies, like Marcone. These types of questions are good to ask in the Dojo over at Appliantology, so you can get feedback from a variety of techs.
This information depends on where you are located, because the prevalence of brands and models varies widely around the country. Therefore, you would want to get this info from your parts supplier. They should be able to tell you the top selling parts for your area.
In order to find the circuit current, you first have to know the total resistance in the circuit. So total circuit resistance is the correct answer.
Hi Cory – the Air Distribution unit, correct? Those videos all play for me, so it isn’t anything on our end. Try closing your browser and/or clearing your cache. That is usually what helps others. Let me know!
Hi Andrew,
Question 8 you figured out.
Question 7 – did what I wrote in my email not help you understand?
“The total current flow equals the sum of the current in the two parallel circuits.” So if one circuit goes to zero, and the other stays the same, what will happen to the total?You can also rewatch the first video in Unit 5 about parallel circuits, particularly the first 5 or so minutes.
Question 9:
Check out this Forum topic to see if it helps:
https://my.mastersamuraitech.com/appliance-repair-course-support/student-forums/topic/midterm-number-9/This is advanced material, so don’t be surprised if it makes your brain hurt a little! Whatever you can grasp will help, and over time if you keep at it, you’ll understand more and more.
I’m going to reach out to one of our techs to help you further.
Power and control are the answers
Hi David,
Did you see the Explanation in the quiz results? “You’re checking to see if the noise filter is capable of putting out 120 V AC. Looking at the schematic, the output is at the points labelled L2 to N2.”
We are encouraging students to keep the basics in mind, rather than getting too lost in the particulars of an unfamiliar-looking component. Just examine the input and output first.
This question states that we verified the power supply (input) is good, so the next step is to check for output at L2 and N2. If it is “good” – you keep moving down the circuit. If you don’t have any voltage, then you know there is a problem with that component, and would then need to determine the best way to proceed, based on what you know (or find out via research) about the component in question. If everything shown in the circuit diagram is inside that “box component”, then you would likely just replace it.
“Electricity is slowly clicking for me but is still fuzzy at times”
That is to be expected! It is not a quick thing to learn. You just have to keep at it, practicing and reviewing, and slowly on you will master it. There’s no magic shortcut, unfortunately.Hi Madelynne,
You’ll start to get some reading assignments in the Kleinert book in the Basic Electricity module.
~ SusanIf you use P = E^2/R, and you only want to find the heat generated by one of the loads in series, then the value for E has to be just the voltage dropped across the load in question. You can do that, but I think it is more straightforward to find the circuit current, then use the second formula for P that you used to find ~1300 watts, which is the correct answer.
-
AuthorPosts
