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Remember that to have electron movement (current), you must have a complete circuit and voltage applied to that circuit (meaning: a difference in charge between two points).
If you are standing on the ground, and touch a neutral wire, what is the difference in charge (voltage) between you and the neutral wire?
December 15, 2024 at 10:30 am in reply to: Module 4, Unit 8: Voltage, Voltage Drop, and Loads #268111 is correct
7: your answer was “About 1,350 heat units”
“Heat units” is not a valid way to express heat. It is “watts” (1350 is the correct numerical answer)10: You are closer. Yes, this is a 240v circuit. But remember that the voltage drop of R1 will be two times that of R2. Your answers of 80v for R1 and 160v for R2 is the opposite of that.
Hi Carl,
FYI, this is the Unit 5 quiz (I edited the title of this topic).
#5: The two circuits shown in the diagram are L1-N1 and L2-N2. They are both 120v circuits. Since we told you the input (L1-N1) was verified, the next step would be testing output (L2-N2). 120v is what we would expect to read.
#7: See Unit 4, the section titled “Load Analysis (identifying the power supply for your Load of Interest)”
#17: Did you see the explanation that shows up in the results of the quiz?
The heating element should be getting 120 V AC at each terminal. The fact that one side is not giving voltage means that something is open on that side. In this case, one of the controls are stuck open.
Hi Ronny,
Quick reminder that exams must be 90% or higher for Certification. Take a look at your Module 1 Exam score. (You have a second attempt available)
The answer is “Freezer evaporator”. The first video in the unit shows how the fresh-food evaporator is in series with the freezer, but can also be bypassed. So, the freezer is always getting refrigerant.
Video tip: did you know that there are transcripts that you can scan through or search? (It’s the symbol in the bottom frame of the video, between “CC” and the gear.) That’s a handy tool when you are reviewing for tests.
That is correct, good job! (I will hide the answers so we don’t give it away to others)
Hi Jozsef,
Please look for an email I just sent to you!Hi Chris,
Did you try this link? Should open the pdf for you, without needing you to join or get other access. If you get a pop-up window inviting you to set up something with Proton, just click the “x” to make it go away, then it should pull up the pdf. I just did that using the Chrome browser as an anonymous guest, so Proton couldn’t recognize me from previous interactions.
https://drive.proton.me/urls/59YNZQYB88#MrYvJmlY1GLc
Let me know if that works.Did you mean its not a motor its a valve that flushes the dispenser so it would be none for my answer?
That’s correct!
Yes, that is.
So it looks like I calculate only the resistance of R2 when finding power
Yes – because we only wanted to know the heat generated by the load “R2” which has 40 ohms of resistance.
Current flow (the rate of electron movement) is determined by the total resistance in the circuit. It is not different at different points – it is the same at every point in the circuit.
But voltage drop and power will be different over different loads in series (unless the loads all have identical resistances)
Yes, that is correct.
In a series circuit, the current is the same throughout the circuit – at any point you’ll measure the same amps. It is determined by the voltage (total dropped across the loads, which will be the same as the voltage supply) and the total resistance. So, 2 amps is correct.
Now, you know the current flowing through R2. You know the resistance of R2. Choose the right formula for P and you should get the right value for the heat (watts) generated by R2.
Hi Leigh Anne,
The quiz question asks what the minimum temperature is
You have a 120v circuit (L1-N) with two loads in series, R1 and R2. R1 = 20 ohms; R2 = 40 ohms. What is the heat generated by R2?
The first step is to find the circuit current, I. Do you know what it is?
Hi Leigh Anne,
Good question!Yes, you could do that, but there are a couple of things to keep in mind.
1.The only score we can see on our dashboard is the most recent one you’ve taken. So, if you accidentally scored lower on your second attempt, we would no longer see your first score. You can prevent this from interfering with earning Certification by archiving all of your emails with your quiz scores, so if you needed to, you could forward proof to me that you had a higher score on a first attempt.
2. We encourage you to understand the correct answers to as many of the quiz questions as possible before moving on in the course, both for the sake of the knowledge itself, but also to increase your chances of passing the Module Exam. Sometimes you can glance at a quiz result and realize what the correct answer is, without needing to retake it. But sometimes retaking the quiz is going to be more effective.
Hope that helps! Let me know if you have any other questions.
See the “Volume Control” video in that unit, starting just after the 5 minute mark.
Hi Denis,
First of all, have you read the summary of voltage and voltage drop at this pinned topic?
https://my.mastersamuraitech.com/appliance-repair-course-support/student-forums/topic/voltage-and-voltage-drop-summary/Voltage drop is specifically the difference in charge that we measure across one or more loads when current is running through the circuit.
If current is not running through a load, then there will be no voltage difference across it.
Does that help? Read through those, and let me know if you have follow-up questions.
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