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Yes, that’s the answer. Do you understand it now?
First of all, did you rewatch the video at the end of Unit 5 where we talk about this?
Equivalent resistance is mathematically reducing two or more loads into just one.
It’s a little easier when we’re talking about loads in series, because all you have to do is add them (we call that “total resistance”). For example, if you have a 10 ohm load and a 20 ohm load in series, from the point of view of the power supply, it “feels” 30 ohms of resistance in the circuit. It doesn’t know that the resistance is divided up into two different loads.
Similarly, if you had a 10 ohm load and a 20 ohm load in parallel, the power supply would “feel” a resistance 6.67 ohms (that’s the equivalent resistance of those two loads). It’s just the way electricity works.
The question asks for the Equivalent Resistance of two loads that are in parallel. Resistance is in ohms. Current (amps) doesn’t come into it.
(I did mention this at some earlier point in this thread.)
Do you understand what we mean by “equivalent resistance”?
Hi Darren,
Things have been very chilly up here, but we’re doing great, thanks!
If you have a DMM with LoZ, then you don’t need a Wiggy.
We have considered selling merch, but haven’t implemented that yet. We love orange, too! (Partly from being Clemson alum.)
Our graphic designer had started working on some ideas a while back – we’ll get him going again and let you know.
Why are you trying to calculate amps there at the end?
Hi Tyler,
Rewatch the first video in Module 3 Unit 5 starting at about 11 minutes.
https://my.mastersamuraitech.com/module-3/basic-electricity-series-and-parallel-circuits/
To successfully answer Question 9 you just need to know the basics of voltage, voltage drop, current, and L1-L2 power supply.
Look at Figure 1 and think about what measurements you would expect to get if the circuit were functioning properly. Remember that we tell you that the element has continuity.
IF the element was heating, what voltage drop would you expect to measure across the element?
Hi Mark,
You are all set – I see the 100% score.
The way our course software words that message is a little awkward. As soon as you start the second attempt, it changes it to say you’ve already used two attempts. It’s just jumping the gun a little bit with that message, for some reason. Sorry for the confusion!
Hi Cole,
I know that can be a little tricky, but just do your best. I will write out fractions like this: 1/2. If there’s something more complicated, use parentheses, like this: 1/(2 + 3) (which would mean that it is 1 over 2+3, in other words, 1/5. Note that you can substitute the words “divided by” for “over”.)
Does that help?
Make sure you are looking at the page numbers on the pages of the book itself, and not the numbering according to the pdf reader. Page 98 in the text has Figure 6-31 at the top of it.
No, you don’t really have it correct.
This is an L1-L2 circuit. There is no neutral line, but we do use a neutral point to do some of the voltage measurements. That’s important to keep in mind.
Have you rewatched the video at the end of Unit 6 to help prepare for this? And then re-read the Midterm Help Page?
That’s correct. Do you understand the whole scenario now for #8?
Correct! So, what does this mean for the main coil – does it have any voltage drop?
is the detector the shunt or the thing being shunted? (That’s what I had asked: “which one is the shunt, and which one is being shunted?”)
I just want to make sure we’re clear!
A shunt is a path that has no resistance. Shunts are used to bypass one or more loads at certain times during an appliance’s operation.
So, between the closed detector switch and the main coil (which are arranged in parallel to each other, so electrons have a “choice” of which path to take), which one is the shunt, and which one is being shunted?
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