Susan Brown

[Susan Brown]

Tip for Question 9: there are 4 correct answers

Think about the sequence of events that led to the problem – spilling stew. Did you read the explanation that showed up in the quiz results?

Since we hear a spark, we know the spark module is at least trying to do its job. Also, since flame is established, we know the spark is being delivered to the correct location on the burner head and that the burner head is delivering the fuel-air mixture to the spark location. Therefore, there’s no reason to suspect the spark module, board, or electrode. The problem must be in the return current.

I reset you.

[Susan Brown]

Hi Joe,

Sometimes a little connectivity glitch can cause a problem with a quiz freezing up. As you’ve seen, it doesn’t happen often.

No worries – I reset you so you can take it again.

[Susan Brown]

😀

[Susan Brown]

Hi Ronny – you found a typo! I’ve changed the “lowest” answer to now really be incorrect.

Thanks for the keen eyes and brain!

[Susan Brown]

Glad you figured it out!

[Susan Brown]

Hi David,

I emailed feedback to you on the ones you missed – did you not receive that email? I sent it around 3:15 pm Eastern time.

Hotmail often puts our emails into the spam folder, so check there. Let me know!

[Susan Brown]

A sense of humor is VERY important!! 😀

[Susan Brown]

Hi David,

The question is, “Question #2 – Measuring DC current is a measurement you will probably never do as a professional appliantologist.”

Your quote above is about voltage.

Current and voltage are different properties, and therefore different measurements.

Paying attention to terminology is important for technicians!

[Susan Brown]

What is the equivalent resistance of the condenser fan motor and the compressor? (Note: the compressor is off.)

First you have to find the resistance of
1. condenser fan motor
2. compressor (when it is off)

What did you find for those?

[Susan Brown]

#10 – watch the video at the end of Mod. 7, unit 2, around the 6 minute mark.

From Module 7, unit 1: “When a switch is not actuated, it is said to be in its “normal” state.”

[Susan Brown]

You just needed to end up back at the module at the end so it was a complete path.

[Susan Brown]

It just has to do with how many decimal points you maintain in the calculation.

For example, 1/30 is 0.0333333…

If you round that to 0.03 and continue on with the calculation, you’ll get around 20 ohms.

If you maintain a few extra “3s” on your calculator, you’ll end up with 18.75 (ish).

Try that on your own and see if you can get the different answers.

[Susan Brown]

Yes – I reset you

[Susan Brown]

so looking at the hot light switches now im looking at the LF-Y if im looking at it correctly it looks like its always supplied with L2 and it gets L1 when the protector bimetal closes.

Sorry, I didn’t catch that you said “protector” bimetal in your reply above. The protector is not in the circuit for the LF hot indicator light.

but now im thinking the lights bimetal switch is the right one not the protector

yep!

I reset you

[Susan Brown]

Sounds like you’ve got it! I reset you

[Author]

Posts