Susan Brown

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  • in reply to: CS7 LOI Circuit analysis #20246
    Susan Brown
    Keymaster

      Good, you’re seeing the right one now.

      So when the switch closes L1 goes through the light and back to L2 through the red wire?

      yes

      Otherwise, follow that BK (J) jumper (the line on the schematic is not continuous) up to that where it joins in near H1.

      in reply to: CS7 LOI Circuit analysis #20243
      Susan Brown
      Keymaster

        Hi Joe,

        You may be looking at the wrong light. There is a single “surface indicator light” in one location on the schematic, and then there are 4 hot surface indicators lights, one for each burner. You want to find the LF light.

        Let me know what you are looking at – how is it labeled?

        in reply to: mod 7 unit 4 case study quiz #20219
        Susan Brown
        Keymaster

          Tip for Question 9: there are 4 correct answers

          Think about the sequence of events that led to the problem – spilling stew. Did you read the explanation that showed up in the quiz results?

          Since we hear a spark, we know the spark module is at least trying to do its job. Also, since flame is established, we know the spark is being delivered to the correct location on the burner head and that the burner head is delivering the fuel-air mixture to the spark location. Therefore, there’s no reason to suspect the spark module, board, or electrode. The problem must be in the return current.

          I reset you.

          in reply to: Mod 2 Unit 5 #20173
          Susan Brown
          Keymaster

            Hi Joe,

            Sometimes a little connectivity glitch can cause a problem with a quiz freezing up. As you’ve seen, it doesn’t happen often.

            No worries – I reset you so you can take it again.

            in reply to: Basic Electricity Exam #20172
            Susan Brown
            Keymaster

              😀

              Susan Brown
              Keymaster

                Hi Ronny – you found a typo! I’ve changed the “lowest” answer to now really be incorrect.

                Thanks for the keen eyes and brain!

                in reply to: Module 3 Unit 5 #20155
                Susan Brown
                Keymaster

                  Glad you figured it out!

                  in reply to: Midterm # 6, 8, 9 #20148
                  Susan Brown
                  Keymaster

                    Hi David,

                    I emailed feedback to you on the ones you missed – did you not receive that email? I sent it around 3:15 pm Eastern time.

                    Hotmail often puts our emails into the spam folder, so check there. Let me know!

                    in reply to: Module 3 Unit 9 Question #2 #20143
                    Susan Brown
                    Keymaster

                      A sense of humor is VERY important!! 😀

                      in reply to: Module 3 Unit 9 Question #2 #20141
                      Susan Brown
                      Keymaster

                        Hi David,

                        The question is, “Question #2 – Measuring DC current is a measurement you will probably never do as a professional appliantologist.”

                        Your quote above is about voltage.

                        Current and voltage are different properties, and therefore different measurements.

                        Paying attention to terminology is important for technicians!

                        in reply to: Module 6 unit 5 question 14 #20138
                        Susan Brown
                        Keymaster

                          What is the equivalent resistance of the condenser fan motor and the compressor? (Note: the compressor is off.)

                          First you have to find the resistance of
                          1. condenser fan motor
                          2. compressor (when it is off)

                          What did you find for those?

                          in reply to: Help with Exam #20131
                          Susan Brown
                          Keymaster

                            #10 – watch the video at the end of Mod. 7, unit 2, around the 6 minute mark.

                            From Module 7, unit 1: “When a switch is not actuated, it is said to be in its “normal” state.”

                            in reply to: CS3 LOI #20130
                            Susan Brown
                            Keymaster

                              You just needed to end up back at the module at the end so it was a complete path.

                              in reply to: Equivalent Resistance in Parallel Circuits #19616
                              Susan Brown
                              Keymaster

                                It just has to do with how many decimal points you maintain in the calculation.

                                For example, 1/30 is 0.0333333…

                                If you round that to 0.03 and continue on with the calculation, you’ll get around 20 ohms.

                                If you maintain a few extra “3s” on your calculator, you’ll end up with 18.75 (ish).

                                Try that on your own and see if you can get the different answers.

                                in reply to: CS7 unit 4 #19613
                                Susan Brown
                                Keymaster

                                  Yes – I reset you

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