Forum Replies Created
-
AuthorPosts
-
Hi Ronny,
Good question!
In our opinion, appliance repair is definitely doable for someone with some physical limitations. We see hundreds of appliance techs at the conferences that we go to, and many of them are not in optimal shape!
There’s very little standing around. You’re on the move, doing several calls a day. We train you how to do as much troubleshooting as possible from the control board, which minimizes the physical work.
You do have to get on the floor at times, and we strongly recommend wearing knee pads to protect your knees.
The most important physical ability is manual dexterity and a little bit of arm strength, since you use a lot of tools to do measurements, machine tear-downs and parts replacements.
You need to be able to do things like pull appliances toward you, and occasionally tip them on their front or side, then put them back into place.
The occasional job that requires heavy lifting (stacked laundry, wall ovens), you can either pay someone to help you or use specialty equipment for this purpose. These are costs that you pass along to the customer. (These types of jobs you might avoid when starting out, until you are prepared.)
You may find that doing appliance repair will help you get into a little better shape, since you’ll be moving around more than with the truck driving.
Hope that helps!
You are correct!
Sorry for the delay in replying. We had meetings all morning.
The only “wrong” thing is that the Midterm is in Module 4, so I’ll move this conversation to that Forum.
Good question! And you’ll learn more about this as you go along in the Module.
Here’s a short description for now:
Electrons respond to voltage.
We get current (the stream of moving electrons) when there is a difference in charge (voltage). As you said, they’ll always move toward the more positive charge.
With AC current, the voltage polarity at the power supply alternates, so that at one moment it is positive, then next it is negative, etc. This causes the electrons to go back and forth in response to the changes.
Does that help?
Hi Robert,
It looks like Danfoss made some updates to their data since the time we made those videos.
That’s definitely on the right track – it depends what exact number you mean for the one that drops “less”, and which load it is. You can email the answers to me so that I can give you better feedback.
Here’s the answer:
Because the two compressor windings are in parallel, you take the equivalent resistance of those first, then calculate equivalent resistance again using that and the resistance of the fan.
Although, since you know that the equivalent resistance will be something less than the smallest resistance, you can also figure out the answer without carrying out all the calculations.
Let me know about the reset…
Hi Chase – I’m checking with the tech experts to make sure I give you the correct answer and will get back to you ASAP. You did pass the quiz – are you sure you want a reset?
great! I just reset you.
Do you want me to reset that quiz so you can retake it?
Hi Eugena,
You’re talking about how the LOI gets L1 and L2.
Good job being “Zen-like” 🙂
What you see is correct, although there is one additional way you can potentially reach L1.
(In other words, there are 2 correct answers to Question 2)
The “inverse of the Rs” formula is for finding equivalent resistance of loads that are in parallel.
When you have loads in series, you want to find total resistance (in order to do things like calculate the circuit current), which is just the sum of the resistances.
Good question!
No, you put the probes on either side of the load. You want to measure one side of the load with respect to the other side.
Rewatch the second video in Mod. 3, unit 8, and look for when he measures voltage across the light bulb that is lit up – that is an example of measuring voltage drop.
Yes, you can calculate voltage drop using E=IxR, but you only have to do that when you have more than one load in series in a circuit.
What if you have only one load in a circuit – what would the voltage drop across that load be?
(This is a big hint that should help you get part of the way towards figuring out Question 8)
Hi Nathan,
Start a new topic here in the Forums about this question and we can help you. I sent the student above an email because he had answers on his exam that I wanted to comment on privately.
Did you look at the Midterm Help Page? We give you suggestions:
https://mastersamuraitech.com/midterm-exam-help-page/
For question 7, we say:
Make sure you understand the scenario. These parallel circuits are functioning normally, then the top branch (element) fails open. We want to know the change in current or voltage drop in the branches and then the overall current draw from L1. The videos at the end of Unit 4 are particularly helpful to review, but also Unit 5.
-
AuthorPosts