Susan Brown

[Susan Brown]

You got it, with one correction.

Voltage doesn’t “travel”, it is present, or felt. Current is what is moving in a circuit (electron flow). So, the electrons are shunted and do not travel through the main coil.

Voltage drop is created by current flowing through a load.

Note – I’ll have to hide parts of your answer so we don’t just give it away to others. The struggle with this question is a great learning experience!

[Susan Brown]

[answer hidden]
Bingo! That is the correct thinking.

What does this mean for the ignitor and booster?

[Susan Brown]

Hi Mike,

If I “Zen” the booster – I get L1 on my left and the main on my right.

On your right, as you are working your way to N, you have two options. Go through the main coil, or go through the closed detector switch.

Why did you choose going through the main coil?

[Susan Brown]

Hi Tim – where do you see that it is said that 4 mega watts is 400,000 watts?

[Susan Brown]

Right now Scott is using this, which he got from Home Depot

Klein Tools NCVT-4IR Voltage Tester, Non-Contact Volt Tester Pen with Infrared Thermometer for AC Voltage, IR Temperature, Great HVAC Tester

[Susan Brown]

Hi Ronny,

Which part of the video are you referring to? (About what time in the video?)

I know he uses water as an example to explain some thermodynamic properties, but obviously we don’t use water as a refrigerant.

[Susan Brown]

Hi Tim,

Did you see the explanation for Question 3? (it shows up in the quiz results after you take the quiz)

The only appliance on the diagram that uses 240 vac is the dryer. Looking at the dryer schematic and following the line from the common on the door switch, you’ll see that the line goes to a tie point. At the tie point, Neutral and Ground are shown tied together. Since Neutral and Ground are not separated, there are only three conductors needed here: L1, L2, and Ground/Neutral. If Neutral and Ground were not shown tied together, then a four-wire power cord would be needed for the extra conductor.

The drawing shows that ground and neutral are spliced together.

For question 9, by saying that the washer “lost neutral”, we mean for you to assume the problem happened somewhere in the washer circuitry.

Here’s the explanation from the quiz:

The schematic shows that the washer gets its Neutral from the dryer. The dryer gets its Neutral directly from the power cord terminal block. So if the washer lost Neutral, this would have no effect on the dryer. How could the washer lose Neutral? The molex connector that supplies Line and Neutral to the washer from the dryer could go bad, a wire could retract, etc. It happens!

Let me know if you have any other questions.

[Susan Brown]

Hi Jason,

The answers to this question usually click into place once you figure out what is going on with the main coil.

If you do the “Zen trick” on the booster and the ignitor, how do you reach N?

[Susan Brown]

Hi Jordan,

If we thought there was a better or easier way to explain Ohm’s Law, we would have done it that way! 🙂

To some extent, it just takes wrestling with it and some time. The quizzes should help you with that, as well as just rewatching the videos, taking notes, and practicing the calculations.

What I found, when I was learning it, is that as I went along suddenly a piece of the puzzle would really click in for me, and then I could go back and understand even more in the earlier videos. It’s a process.

I created this blog post to help people who struggle with the math aspect of it. Have you gone through this? It’s designed for you not just to read, but to use pencil, paper, and calculator to “play around” with it.

https://my.mastersamuraitech.com/appliance-repair-course-support/student-forums/topic/math-and-ohms-law/

Lastly, asking more questions of us here in the Ask the Teacher Forums is a key component to learning. Just take anything you don’t understand – a video, or a quiz question – and use that as a starting point, and we’re happy to go back and forth and help you.

[Susan Brown]

There are occasional mentions in the course, but there’s not that much that’s different about these units compared to the usual stand-alone ones other than configuration. The machine compartment is often located on top. And, as you would expect, they are designed to be worked on from the front, since you can’t just roll them out to access the back.

[Susan Brown]

Question #1 – What characteristic of a heating element does NOT make it an electrical load?

So, we’re looking for the characteristic in the list that is not the thing that makes a heating element a load.

You answered:

It has a voltage drop across it when current flows through it.

This is one of the key characteristics of a load.

[Susan Brown]

Thanks for asking!

We do not have a hard copy available. One reason is that we update the material over time. Another is to keep our proprietary teaching secure. Unfortunately, there are people out there who try to copy and sell our information.

What we strongly encourage people to do is take thorough notes as they go through the course, especially from the videos. And, as long as you have access to the courses, to review the course material and add to your notes.

[Susan Brown]

Most residential refrigerators are “stand alone” – meaning, they are not installed or attached to cabinetry in any way. They are rolled into place (and perhaps connected to a water line.)

“Built in” would be like most Sub-Zeroes and other high end refrigerators that are actually installed into the cabinetry in some way.

[Susan Brown]

Yes, the answer is power. For a load to do work, it needs both voltage and current, which is “power” (P = I x E)

[Susan Brown]

You are on the right track.

Resistance is not the right answer because a load has a resistance by definition. Whatever material it is made from has a certain resistance.

According to that understanding a correct answer would the load would require voltage and current to do work.

That is correct. And the term we use for the combination of voltage and current is power.

Think about the common Ohm’s Law formula for power: P = I x E

Power is voltage times current. So, that is the correct answer here.

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