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Hi Daniel,
1/30 = 0.033
1/50 = 0.020.033 + 0.02 = 0.053
1/0.053 = about 18.75
(Note – the calculator turns 1/30 into 0.0333333… Depending on how many “3’s” you keep, the final answer will vary slightly in terms of the number after the decimal point. Would be find to round it to 19 ohms.)
Hi Rodney,
Great question! That’s not a short, because you’ve got a load in the circuit.
A short is some path from Line to N that does NOT have a load in it.
When you see L1 on both sides of a load, this means that there is no voltage drop across the load. What does this tell you about current? Is it flowing through that load?
P.S. You might notice that I moved this to a new topic
Hi Ronny,
You will learn the most important things you need to know about Refrigerator Repair in our course – how they work, how to troubleshoot them, and common repairs. We introduce you to sealed system repairs. Not all techs do sealed system work, since approximately 90% of repairs on residential refrigerators do NOT involve the sealed system.
The new procedure that you mentioned is actually optional. Not all techs who work with R600 (isobutane) use the Lokring system. That topic is still in flux right now.
We wrote up a little article about all of this – check it out and let me know if you have any questions.
https://mastersamuraitech.com/how-do-i-get-sealed-system-training/
Sounds like a good plan!
Hi Everardo,
On our Tools list, the items are linked to Amazon.com if you want to buy them there.
https://mastersamuraitech.com/list-of-basic-tools-to-have-on-hand-for-every-service-call/
Appliance repair techs don’t usually do board-level repairs such as replacing a resistor. It’s good to know what they are and how they work, since we deal with electronic boards on a regular basis. But when you’ve determined through troubleshooting that a board is malfunctioning, the vast majority of the time you will just replace the board. Repairing control boards is its own specialty, and doesn’t make sense to do in the context of in-home appliance repair.
Hi Ronny,
That is all correct except for the conversion at the end.
A milli ohm is a smaller unit of measure than a regular ohm. Dividing the 250,000 by 1,000 would give you kilo ohms, or k-ohms. You would multiply by 1,000 to get milli-ohms.
Hi Ted,
According to my notes voltage is known as potential energy and the Electromotive Force. The force that causes electrons to move from negative to positive. Measured in volts and referred to as V or E.
That’s correct – voltage is the force that causes the movement. It is not the movement itself.
The “flow of electrons” is referring to that movement of electrons. That’s what we’re asking for in Question 10. Do you know what we’re asking for now?
June 28, 2020 at 11:50 am in reply to: Refrigeration….Just when you thought it was safe to be here; I’m Baaaaaack..! #19304Haha – always good to hear from you!
Yeah, it looks like our steamer is no longer available. Search Amazon for “handheld steamer” and look at reviews.
These are steamers used for cleaning, not for clothes.
Here’s a similar one that I found
Did you watch the videos at the end of Unit 4? We cover this exact scenario.
Remember, you got part 1 correct on your exam. In our question, the diode fails open. So we want you to tell us what happens to the current when that failure happens. In other words, the circuit was operating correctly then had that failure. So, it goes from having current to having no current.
You also got part 2 correct.
3. The fan motor is the only load in that particular circuit. And the resistance of the motor is what it is – it can’t change. Rule of thumb – what happens in one parallel circuit doesn’t affect others that are in parallel. (The overall current will change.)
Part 4 is correct.
You’ve got this correct now! The 3 answers add up to 119, which is close enough. It’s just off a little because of rounding of numbers along the way.
Hi Ronny,
Glad to help! Loads will only split up the voltage drop if they are in series with each other, but the ignitor and booster are in parallel with each other. Plus, we didn’t give you any idea of what the resistances are of the loads to know how to divide them up.
Hmmmmm….
This question trips up a lot of folks, but once you see what’s going on, you’ll have an “a-ha!” moment. I’ll help step you through.
First, try doing the “Zen trick” on the booster. How do you reach N?
Hi Zachary,
If you go back to the Operational Overview video in unit 2, starting around 1 minute or so, you’ll hear that the refrigerant enters the evaporator as a liquid. It absorbs heat from the air and then boils and turns into a gas.
Does that help?
Look at the video again, for example around the 10 minute mark, and again later in the video, his discussion about Cam 6. When those contacts are closed, what is being supplied to the motor windings?
Yes, that works.
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