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That’s what we’re here for!
Figure 1 is the schematic – it won’t show what the error is. You have to use the measurements to determine what is going on – just like in real life! You aren’t able to see the entire circuit in the appliance – you are using measurements to deduce them.
In Figure 2, we deliberately disconnect a wire in order to do the half-splitting technique. That’s not the same thing as showing you where the fault was in Figure 1.
When we have an L1-L2 circuit, and there is an open on one side or the other, you cannot tell from measurements which side is open because both sides have a hot line.
In an L1-N circuit, you would be able to tell without half-splitting. If you measured 120v on one side of the load wrt N, you would know that the open was NOT on the L1 side, otherwise the voltage wouldn’t be felt at the load.
If you measured 0 volts from both sides of the load wrt N, you would know the open IS on the hot side.
But with both sides being hot, you can’t tell from the scenario in Figure 1 which side is at fault without disconnecting the circuit and re-measuring.
Do you see how that works?
Yep! So, that’s the important bit of info that Figure 1 is giving us. Do we know – in Figure 1 – where the open is?
Good!!
What is the general cause of current not flowing, even though there is some voltage present?
Correct again!
However, the measurement from L1 to L2 in Figure 1 is zero. So, we have no heat and no voltage drop. Does this change your mind about current flowing in the circuit?
Remember, you can measure voltage (potential) when current isn’t flowing.
Correct. Yet, we are getting no heat in this dryer.
But there is another effect that we see when current goes through a load – it’s something you measure with your meter, and we had a whole unit on it…
What happens when current flows through a load?
The element is a load. If electrons are moving in this circuit (current flow), then they’ll be going through the element. What would that cause?
I’m glad I asked!
If current is flowing in L1, is it also flowing through the element and on the L2 side?
Hi Daniel,
Yes, that’s exactly it.
Let’s go even further to help you understand this scenario. Based on the information we give you, is current flowing through the circuit in Figure 1?
I’ve asked our Appliantology admin to help you out.
You could also review the unit in the Appliantology 101 course about searching for manuals, and how to request a manual if the search doesn’t turn up what you need.
https://my.mastersamuraitech.com/module-1/searching-manuals-appliantology/
July 6, 2020 at 11:47 am in reply to: Refrigeration….Just when you thought it was safe to be here; I’m Baaaaaack..! #19343confirming:
The first scenario – that the freezer seems cold – is not saying that the freezer is at the proper temps. It is just stating the way the customer usually observes the failure sequence. They rarely know what the actual temperatures are. The first place they notice the failure is in the fresh food compartment, because it only takes a few degrees of warming to get into the food spoilage zone there.
Question 12, we are telling you that the freezer temperatures are normal, which would not be the case if the defrost system were failing.
Hope that helps!
Hi Robert,
I think you are talking about Unit 4 – correct?
There are two correct answers to this one.
You chose one of them correctly – Through L1 to H1 in the infinite switch
And as you said above, the other path for L1 is through the bimetal switch.
So – your explanation is correct.
Have you signed up for your free student membership at Appliantology? The application form is in the Appliantology 101 short course.
Appliantology is where you can get the manuals that you need.
July 4, 2020 at 10:29 pm in reply to: Refrigeration….Just when you thought it was safe to be here; I’m Baaaaaack..! #19337Hi Darren,
My first thought is this,
A common complaint you’ll hear a lot in the field is that the freezer seems cold but the fresh food compartment is warm.
I think the word “seems” is important. Most likely, if the defrost system has failed, the freezer is starting to warm, but the customer hasn’t noticed yet.
In Question 12, we are saying that the freezer compartment temps are normal.
I’ll get others on the Team to look into this and see if there’s any further clarification that would help.
Hi Daniel,
1/30 = 0.033
1/50 = 0.020.033 + 0.02 = 0.053
1/0.053 = about 18.75
(Note – the calculator turns 1/30 into 0.0333333… Depending on how many “3’s” you keep, the final answer will vary slightly in terms of the number after the decimal point. Would be find to round it to 19 ohms.)
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