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Okay – now we’re onto something.
In a series circuit, is the current the same throughout the circuit, or does it change at different points in the circuit?
(We covered this in unit 5)
You got it!
Well, we know the common mistakes students make on these questions, so we often put those answers as choices. Not to make the quiz unnecessarily difficult, but to reveal to the student that they need to improve their understanding.
For Questions 7 and 8, you’ve got two loads in series. The resistance of the first one is 5 ohms, the second one is 32 ohms.
First question I’d like you to answer:
Based on what we’ve taught, which one would you expect to generate more heat?
(Answer that, then I’ll give you a tip on where to look for more help on this.)
I’ll get there and thank you
We’re glad to help you get there!
Hi Michael,
The current in a series circuit is the same at every point in the circuit. It’s just the way electron movement works. If electrons are moving in a circuit (if there is voltage and a complete circuit), then they will all move at the same rate.
What that rate is is determined by the *total* resistance of the loads in the circuit.
So, a 120vac circuit with 20 ohms of total resistance in it will have a current of 6 amps (at every point in the circuit). That will be true whether it has one load with 20 ohms, or two loads of 10 ohms each.
Does that help?
Hi Joe,
Here’s the paragraph from Mod 7, unit 1:
It’s also not uncommon to see switches test fine with your ohm meter but then not work right when they’re in a live circuit actually switching voltage. This is called “failing under load.” That’s why I personally prefer doing my troubleshooting on a live circuit and testing for voltages rather than checking for continuity. Continuity tests are okay, sometimes necessary, sometimes expedient. But the gold standard for testing components like switches is live voltage testing.
Here are the 3 answer choices for the quiz:
It’s not actuating properly.
It checks good on continuity but fails in a live circuit.
It’s having trouble carrying its weight.Hi Steve,
Good question! Appliance techs don’t need an Oscilloscope for their work in the field. The one you see in the video is primarily used for training/teaching purposes, rather than diagnostics.
Hi Rudy,
Thanks for your comments.
We’ve had about 2000 students go through the course over the past few years, but are always open to student feedback. I’ll take a look at the items you’ve mentioned.
But I also wanted to point out that we have these Ask the Teacher Forums to account for the fact that everyone has different needs when it comes to training and learning. You do have two attempts available on each quiz, as you know, and we also have the reset program. So, if after taking a quiz for the first time there are questions that aren’t clear to you, just ask us to clarify!
April 10, 2020 at 10:58 am in reply to: Mod. 03 Unit 03: Voltage, Current, Resistance, And Power – Quiz Question #11 #18870Good question, Matt.
There are two resistances in the circuit – the loose connection and the element.
To get the heat generated by one of the resistances only, the “E” in the equation P=IxE would have to the be voltage drop across that individual load, not the total voltage.
So, you’d have to calculate voltage drop across the loose connection.
This is do-able, but most students have an easier time of following the logic behind the technique shown above in V’s post and in the video. And it requires fewer steps.
Here’s how you could do it.
The total voltage dropped across the entire circuit is 240vac.
The resistances (in our video scenario) are 32 ohms and 5 ohms, so total is 37ohms
Voltage drop across loose connection is directly proportional to the resistance of that connection, so is
240 (5/37) = 32.4 volts32.4 x 6.5 = 211 watts
so – that’s a little more complicated than just using P = I squared x R
April 9, 2020 at 6:50 pm in reply to: Mod. 03 Unit 03: Voltage, Current, Resistance, And Power – Quiz Question #11 #18866Yes – that is correct – good job!
FYI – I’ll need to hide part of your answer so we don’t give it away to other students.
Good question!
You’ll get a feel for these numbers as you go along. Here are a few guidelines.
Ohms and Watts do not need to be reported with any decimal places – whole numbers are fine.
With the example you gave, of 1350 watts vs. 1352 watts, those are essentially the same. When you’re talking about overall values in the hundreds or thousands, a few watts one way or the other in the “ones” place doesn’t matter.
Amps is where you usually will see smaller, more precise numbers, like 3.2 or 6.5.
Hope that helps!
You’re welcome! So far so good.
Hi Don,
It looks like Danfoss made some updates to their data to be more accurate. The pressure values they give now are about 0.2 psi lower than they were when we made that video. It’s a small difference — and wouldn’t really be consequential in troubleshooting.
Hi Darren,
The Midterm is a uniquely challenging exam in the course – that’s why we created that study sheet.
The Final exam is largely based on the unit quiz questions that you encountered throughout the course. The biggest difference is when you get to the Open Answer exam and have to write definitions and do a few calculations on your own. The final exam has a higher first-attempt passing rate than the Midterm, FYI.
So the best way to study is to review each unit and quiz, to refresh your memory. If you’ve been keeping a notebook, that will help a lot.
Keep a calculator, pen, and paper handy.
April 4, 2020 at 12:23 pm in reply to: 1.9: Core- Operational Overview Top-Load Washer Unit 5 #18849You found a typo – thank you! It’s supposed to be “drain pipe”.
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