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Susan Brown

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Viewing 15 posts - 1,246 through 1,260 (of 1,890 total)
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  • in reply to: question 18 #18555
    Susan Brown
    Keymaster

      Hi Ed,
      I just emailed you about this…

      in reply to: Final Exam Q. 7 #18487
      Susan Brown
      Keymaster

        A short or an open? These terms have precise meanings.

        From Mod 3, unit 1:

        Short: A condition that creates a circuit that offers no resistance to the current flowing through it. A direct short will cause a fuse to blow, or possibly start an electrical fire.

        Whereas an open is just that – some break in the circuit (open switch, broken wire, for example) that prevents current.

        If the fault is on the L1 side, how do you explain this measurement?

        You use your meter to test for 120 V AC from one of the terminals of the light to neutral and you read 120 V AC on your meter

        in reply to: Fundamentals Overall Question #18478
        Susan Brown
        Keymaster

          Hi Darren,
          The Final Exam covers material from the entire course.
          🙂

          in reply to: Final Exam Q 29 #18476
          Susan Brown
          Keymaster

            Yes, that’s correct!

            in reply to: Final Exam Q. 7 #18474
            Susan Brown
            Keymaster

              You haven’t been asked this exact question, but you just have to think about what the measurements are showing you.

              It’s a safe assumption that we’re talking about a 120vac circuit.

              We’re telling you the light bulb and receptacle that the light bulb is in are good.

              There will be two wires going to the bulb, correct?

              One is Line, what is the other?

              Then, think about these two voltage measurements, and what you can conclude:

              1. one side of the bulb has 120vac wrt N
              2. when you read across the bulb, you get zero.

              Let me know what you think…

              What

              in reply to: Clarification #18388
              Susan Brown
              Keymaster

                Well, much better to over-think than to under-think! In my opinion, you were just thinking it through. We’re always happy to help.

                in reply to: Clarification #18381
                Susan Brown
                Keymaster

                  Correct, 1 and 2 would not be able to get to N if a break happened there.

                  This does not change their status as being in parallel with each other. The electrons that go through either 1, 2, or 3 (when there is no open anywhere) do not have to go through one of the other loads to get to L1 or N.

                  in reply to: Clarification #18379
                  Susan Brown
                  Keymaster

                    Both of those diagrams show 3 parallel circuits. If they are functioning, they are electrically equivalent. (Assuming the loads are the same.)

                    The slight difference in configuration only makes a difference in terms of how a break in the wire at certain points would affect the other branches, which seems to be what you’re getting at.

                    in reply to: Clarification #18378
                    Susan Brown
                    Keymaster

                      Do you mean where I put the “x” below?

                      circuit with a break

                      If so, the “Zen trick” will determine this for you… what do you think? Label the parallel circuits 1, 2, and 3. (Circuit 1 would be the one closest to L1, circuit 3 closest to N)

                      Good question, by the way.

                      in reply to: Clarification #18374
                      Susan Brown
                      Keymaster

                        Hi Ed,
                        I’m having a hard time figuring out what you’re asking. Are you talking about these diagrams?

                        in reply to: CS2: Load of Interest Quiz #18360
                        Susan Brown
                        Keymaster

                          Hi Duane,

                          It’s because that is what the 4031 error code identifies as the suspect load when we did the diagnostic mode (see the previous unit- look especially at the explanation for Question 3 in that quiz).

                          in reply to: Req equation #18358
                          Susan Brown
                          Keymaster

                            Hi Tim,

                            Here’s a video that shows the calculation (using different values for the resistances). See if this helps.

                            Also, some people get a slightly different answer from us, depending on how you treat the decimal numbers (if your round them off differently than we do).

                            https://www.youtube.com/embed/iHB3lxdc68E

                             

                            Let me know if this helps.

                            in reply to: Reading Schematic Drawings #18331
                            Susan Brown
                            Keymaster

                              Hi Robert,
                              That question is best to handle by email – I’ll send you a note now…

                              in reply to: Reading Schematic Drawings #18328
                              Susan Brown
                              Keymaster

                                Hi Robert,

                                A noble goal!

                                You’ve already got a great start, by taking the Core course. That gives you a solid introduction. I would encourage you to watch the videos in Basic Electricity and the Troubleshooting Module more than one time. Also, ask us questions here if there’s anything you don’t quite follow.

                                We have other courses that will give you more training and practice: Advanced Troubleshooting and the Oven & Range Repair.

                                We also have dozens of hours of webinar recordings that you can watch at Appliantology. Many of them involve going over schematics, or doing case studies using schematics, etc.

                                There are no short-cuts to becoming proficient at reading and using schematics. It takes time and practice. Just be sure to use all of the resources you have available both at Master Samurai Tech and Appliantology!

                                in reply to: Troubleshooting a 2-Speed motor problem in a top load washer #18277
                                Susan Brown
                                Keymaster

                                  Hi Davy,

                                  In a split phase motor, the start direction of the motor depends on the polarization of the start winding relative to the main winding. (Polarization of the winding is which end gets Line and which end gets Neutral.)

                                  In order to reverse the direction, the motor has to come to a complete stop, then restart with the polarization of the start winding reversed from the original direction. This is what cams 2 and 4 are doing.

                                  Make sense? We do cover this in more detail in the Washer & Dryer course.

                                Viewing 15 posts - 1,246 through 1,260 (of 1,890 total)