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Susan Brown

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Viewing 15 posts - 1,396 through 1,410 (of 1,968 total)
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  • in reply to: Half-Splitting #17746
    Susan Brown
    Keymaster

      Hi Dean,

      We discuss and demonstrate Half Splitting in the second half of this unit:

      https://my.mastersamuraitech.com/module-5/using-schematics-to-troubleshoot-appliances/

      in reply to: Mod 3 Unit 5: 18.75 ohms? Can’t get that….please explain #17733
      Susan Brown
      Keymaster

        Okay, I see what’s going on.

        1/30 is 0.033333…

        So, the difference is just in the rounding. You used 0.03.

        1/.0533 = 18.75

        Not a significant difference as far as ohms readings go, so either result would be fine.

        in reply to: Mod 3 Unit 5: 18.75 ohms? Can’t get that….please explain #17730
        Susan Brown
        Keymaster

          1/.02 + 1/.03 = 1/.05

          That’s not quite the formula, and it’s also not the way you can add fractions. Let’s back up a bit and step through it.

          The two resistances are 30 and 50 ohms.

          So the formula is 1/(1/30 + 1/50)

          The rule with multi-step calculations is that you always do what’s in the parentheses first.

          What is 1/30 + 1/50? (It is not 1/80… use your calculator to turn each fraction into a decimal number… 1 divided by 30, etc.)

          Then add those two decimal numbers together.

          Then you would do 1 divided by that result.

          What do you get?

          in reply to: Parallel loads and voltage drop #17728
          Susan Brown
          Keymaster

            What is Kirchhoff’s Law? (from Unit 8)

            in reply to: Parallel loads and voltage drop #17726
            Susan Brown
            Keymaster

              It depends. What if a load is the only one in the circuit? Do you need to calculate the voltage drop using an equation?

              in reply to: Parallel loads and voltage drop #17722
              Susan Brown
              Keymaster

                Hi Rodney,

                I moved this to a new topic, rather than having your question tag onto an old one.

                Good job seeing the shunt!

                Let’s start with having you answer these two questions –

                1. What creates voltage drop?
                2. Which of the 4 loads have current going through them?

                in reply to: Unit 12 Basic Electricity Module Exam #17719
                Susan Brown
                Keymaster

                  Hi- yes, this is a different exam. We describe it there on the Midterm unit. It’s a challenging exam, so you definitely want to take it when you will have a block of uninterrupted time!

                  in reply to: Module 1 Unit 7 Question 13 #17715
                  Susan Brown
                  Keymaster

                    You’re welcome!

                    in reply to: Series Circuit #17710
                    Susan Brown
                    Keymaster

                      Hi Paul,

                      Unit 5 will get into that, but the answer is yes. If there is an open anywhere in a series circuit, it will stop current from flowing in the entire circuit.

                      in reply to: Module 1 Unit 7 Question 13 #17709
                      Susan Brown
                      Keymaster

                        Hi Roy,

                        pushes against the magnetic field of opposite polarity

                        I highlighted the problematic word… can you see how this is incorrect?

                        Susan Brown
                        Keymaster

                          Hi Chase,

                          We did make some improvements to the quiz questions in Basic electricity last week. Sorry for the confusion! However, the two questions that were changed (12 and 13) are not in the pool of questions for the Module exam. You may notice a few others were changed in other units, but those also will not be on the exam.

                          in reply to: Voltage drop #17703
                          Susan Brown
                          Keymaster

                            Good! I just sent you an email

                            in reply to: Final Exam Part 2 Question 26 #17690
                            Susan Brown
                            Keymaster

                              A fuse is a switch which doesn’t do work so there is no voltage drop across it right? Disregard my other answer unless I am wrong here but I believe I am right

                              That’s it!

                              in reply to: Final Exam Part 2 Question 26 #17687
                              Susan Brown
                              Keymaster

                                That’s right.

                                In this question, we say,

                                For the light to be on, what is the correct voltage drop across the fuse?

                                So, we know the fuse hasn’t blown open, since the light is on. Is it currently doing work?

                                in reply to: Final Exam Part 2 Question 26 #17685
                                Susan Brown
                                Keymaster

                                  Loads do some kind of work when current flows through them – produce heat, motion, light, etc. What does a fuse do?

                                Viewing 15 posts - 1,396 through 1,410 (of 1,968 total)