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Nick Reyes

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  • in reply to: Module 1 Unit 4 #22560

    Never mind it just clicked for me -15 is a higher boiling point due to the fact that it is closer to 0. wow I do feel silly.

    in reply to: Midterm #21810

    Make sure to blackout the numbers in the chat above

    in reply to: Module 4. unit 1. exam question 4 #21809

    E=I*R

    in reply to: Module 4. unit 1. exam question 4 #21782

    Resistance multiplied by amps squared

    in reply to: Module 4. unit 1. exam question 4 #21758

    Yes question 2,3,4 are about the same circuit I just realized.

    The information I calculated in question 3 was how many amps there are in the circuit.

    The current doesn’t change in a series circuit as it goes through loads.

    in reply to: Module 4. unit 1. exam question 4 #21747

    1. The question is asking us to figure out what the voltage drop across each load in a series circuit.

    2. There is 120 vac supplying the circuit.
    The first load is 10 ohms.
    The second load is 20 ohms.
    The third load is 40 ohms.

    3. Voltage squared divided by resistance (ohms) equals watts(power)

    Voltage divided by resistance (ohms) equals current (amps)

    Answer: I would say V/R = A so we can find how much current(amps) is flowing through that part of the circuit.

Viewing 6 posts - 1 through 6 (of 6 total)