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Yes, that was great! I appreciate you taking the time to clear that up for me. Thank you!
That does help clear things up, but are there any instances where the voltage drop reading would be less than 120 vac when the load is working (as if the load was partially using current)?
I believe the current would be the same throughout the circuit.
Okay, so is it simply E=IxR that I need to know or is it E(voltage drop across load)= I(current flow through load) x R(resistance of the load)?
