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Walter Baumy

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  • “In normal conditions, how is Neutral supplied to the timer motor?”

    Is this the question you’re asking about?

    in reply to: Module 4, unit 1 Ohms Law #7474

    Got that if it’s got current going through it you measure voltage drop, if not then it’s voltage.

    I’ve got the simple version down.

    So lemme ax you dis.

    It’s like testing a single wire with 120v voltage present. There is no potential from any part of the wire to any other part of the same wire. But if there’s a load that voltage becomes measurable at the load? So hypothetically on a ungrounded or open neutral scenario on a 120v heating element, measuring both sides will give you 0 but either side to ground or neutral will give you 115-120 and that is true voltage because the potential is there. But when the neutral is connected and the element/anything is pulling any amperage you can measure 120 at the element/anything terminal to terminal and that’s called a voltage drop.

    So is it not really true voltage if it’s under load, path of least resistance coming into play here? Is what I’m understanding it as correct? I’m after the why is it called a “Voltage drop”. I’ll google it.

    Or is it simply you have to call it a voltage drop, stfu and keep on with the course? lol. You can tell me that too.

    Or if it’s covered in another course that I’m not enrolled in I get that, just have my curiosity sparked with this.

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