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Samurai Appliance Repair Man

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  • in reply to: Module 6 – Case Study 2 #27003

    Pop quiz 1 = 240 (subtracting a negative is the same as addition)

    Correct!

    Pop quiz 2 – You would not measure a difference. The 120 volts coming from L2 would be present at both points, so the difference would be zero.

    Correct again!

    Bonus – I think it was called half splitting, but I remember the technique from the core. I think it would be good for me to review though.

    Correct yet again!

    Sorry to keep you, feel free to move on.

    It’s fine, that’s why these forums are here!

    In this case, the element is bad. So I can’t measure L2 on both sides of the element. This is what I mean, whether or not it is correct….

    This is correct. If the element is open, it’s electrically the same as the two wires being disconnected from the element and measuring at the disconnected wires.

    The element is open, whether it is the element or the connections etc., current can’t pass through it.

    That’s right.

    Scenario 1: the board has killed power to P1-1 because it does not sense the bake element, but it has not killed power to P2-6 because L2 is present for the upper right convection element (we assume). As long as P1-1 and the connecting wires are still intact, would I still measure 120V, because this is the difference between the V being supplied by L2 wrt L1 (the open bake element is not allowing current from L2 to reach the other side)?

    No. If P1-1 is electrically open (because the board is not closing the relay to supply L1, for example), then you’re measuring the voltage difference between L2 and Open. This is a situation where, if you’re not using LoZ or a loading meter, you may measure some ghost voltage but you are not measuring the difference between L1 and L2.

    Here’s a video demonstrating ghost voltage in a wall oven that looks eerily similar to the Acme wall oven in this case study.

    https://youtu.be/vBiRjgMIuSE

    Scenario 2: the board hasn’t killed power, and I would read 240V regardless of the open status of the element because the difference between these two points, due to being out of phase, is 240V.

    Correct!

    in reply to: Module 6 – Case Study 2 #27001

    Or I guess I might see 120volts? Because L2 would still be active (bc the convection element is working)

    Remember that when we talk about “voltage” in a circuit, it’s shorthand for saying, “the voltage difference between two points.” That’s why it takes two leads to make a voltage measurement.

    In a 240 VAC circuit, you have L1 and L2. L1 and L2 to Neutral is 120 VAC. L1 to L2 is 240 VAC. But if each Line is 120 VAC wrt Neutral, then how can you have 240 VAC from Line to Line if it’s supposed to be a difference between two points? Don’t they simply add the 120 VAC together to get the 240 VAC?

    Nope. Still a difference, meaning L1 MINUS L2. (Or L2 MINUS L1, works both ways). It works because L1 and L2 are 180 degrees out of phase with each other so, wrt Neutral, they are two distinct phases of voltage. In a split phase power supply, like most residences in North America, the two phases are 180 degrees apart. Meaning that when L1 is +120 VAC, at that same exact moment in time, L2 is -120 VAC.

    Pop Quiz: What’s +120 VAC – (-120 VAC)?

    What all this is getting to is realizing that, in a 240 VAC load, like the bake element in this case study, if one Line is missing, you will still only read 0 VAC across the element even though the other Line is present.

    And how can this be? Because he IS the Kwisatz Haderach!

    Sorry, I had a Dune moment.

    Pop Quiz: Suppose L1 is missing but L2 is present (vice versa is same outcome). You place your meter probes on each element terminal and energize the circuit. What voltage difference will you measure?

    Bonus Question: What troubleshooting move might you deploy to determine which Line is missing?

    Voltage looks like p1-1 to p2-6.

    Correctillia!

    in reply to: Module 6 – Case Study 2 #26998

    1. I followed the case study and understood. But why aren’t we checking voltage before ohms? Is this because we figured it was the bad element based on the error code and logic? I know live tests are preferred, I figured we would want to check that the board was providing L1 and L2 appropriately before relying on an ohms test.

    Excellent question! You said the answer: we’re getting an error code for the upper bake element. That means the board is sensing the presence of the element during its POST (power on self test). Since the schematic/wiring diagram does not show a sensing line (a switched line back to the board), it is probably doing this via current sensing. You need volts to make amps.

    Also, since the board is throwing this code, the usual algortihm is to kill supply voltage to the coded component. So measuring voltage may not be an option.

    But still, checking the supply voltage is a solid troubleshooting step.

    Pop Quiz: Where would you place your meter probes to see if the upper oven bake element is getting its supply voltage?

    2. The upper right convection oven element, we assume, is functioning properly because there is no error code. Does the bake element get L2 through this convection element? Most of the schematics are not drawn like this (this being a wiring diagram). I mean, based on the drawing, it is impossible for the upper bake oven to get L2 if the convection oven is not getting L2. Is this correct?

    Look carefully at the schematic section with the upper bake element.

    See how the line for the bake element tags off the connection to the convection element? That means L2 for the bake element “daisy chains” and goes on to the bake element. The bake element and the convection element are in parallel, not series. You will encounter loads in series in appliance repair but this is not one of those times.

    Also, manufacturers play loose with the terms “schematic” and “wiring diagram”. This diagram is more like a pictoral schematic. The simple distinction between a schematic and a wiring diagram is this: if you can easily trace the power supply circuit for your LOI on a diagram, it’s a schematic, not matter what the manufacturer calls it.

    3. Can I circuit breaker on without the heat on for the oven, and disconnect only one of the connectors to measure ohms? The question seemed to imply I need to either kill power or disconnect both sides. Can I just disconnect one of these and measure from the wire end to the other connector?

    Yes. As long as the circuit for the LOI is dead AND at least of the leads to the LOI is physically disconnected (either at the load or at the EEPs for the load at the board), you’re good to go.

    Good questions, keep ’em coming!

    in reply to: Case Study 1 questions #26987

    Almost half the service calls I go out on are appliances I have never disassembled. Especially true for the warranty calls because they’re so new. This is where prediagnosis makes all the difference. I always get the model number for every service call. I pull all the technical literature for that model and load them on my ipad. I’ll review the schematic with the problem statement to select my load of interest and read its circuit. I’ll bookmark any relevant disassembly instructions for both troubleshooting and repairing so everything is ready to go on my ipad.

    Here are three workshop videos you should watch. You’ll get a lot more confidence for runnning calls after you’ve watched them.

    The Samurai System for Service Call Excellence

    Appliance Service Call Structure and Troubleshooting Strategies

    Troubleshooting Strategies for Computer-Controlled Appliances

    in reply to: Case Study 1 questions #26985

    1. Knowledge check – hypothetical. Is there any reason I can’t do a similar measurement to the answer by disconnecting PR1 and measuring the PR1 wire end to the DLB connector? If yes, thank you. If no, can you explain.

    That would work!

    2. For the stretch question of calculating ohms, how do I know if I should use the 3600 of 4000 watts? I see it is based on the size but did I miss this somewhere?

    When they give a range like that, I just use an average value. So in this case, if you use 3800 watts and work the problem, you get a little over 15 ohms. There’s only one answer close to this.

    3. Generally, to this point, I have understood the concepts and answered the questions correctly. But I consistently am asking myself how to physically do the tasks. For example, how do we access the oven relay board? How do I replace the TCO? Is this information that will be called out elsewhere in the manual for the appliance, covered later in the course, or just something that needs to be learned outside the course?

    Do you have your Appliantology membership yet? You’ll get disassembly help from service manuals and Youtube videos. You can download service manuals from Appliantology. You can also get lots of disassembly insight from the exploded parts diagrams available at Appliantology or many online parts vendors such as AppliancePartsPros.com.

    Disassembly is the easy part of our job. The hard part is troubleshooting. This is the lost skill in the appliance repair trade today. Many guys will start tearing down right away. This is NOT troubleshooting!

    The rule is this: Minimal disassembly for troubleshooting. Save the teardown for the repair when you have the needed part.

    Most appliances today are computer controlled. That means the main single-board computer often serves as a central troubleshooting location for the rest of the machine since “all roads lead to Rome.” That’s what EEPs are for. You identify these convenient testing locations from the schematic using EEPs.

    in reply to: Sensing a shorted element #26973

    RE: the GFCI question. The Heater Sensing works by sensing voltage between the heater sensing port and L1. GFCIs work by sensing a current imbalance between Line and Neutral. The assumption is that they should exactly equal and,if not, the missing current is going to ground, ie., ground fault.

    in reply to: Sensing a shorted element #26972

    So am I wrong for saying the heat sense circuit and isolating resistor are pretty much built in safety circuits for the type of conditions?

    I’m not sure about safety because the other thermal controls are explicitly there for that purpose. I think the heater sensing is there to assist the technicians in troubleshooting. Especially since the tech sheet says that these codes are not displayed to the customer, only in service mode.

    The isolating resistor is there to allow the heater sensing port to sense a grounded element. Heater sensing takes place before the heater triac or relay closes and with the motor running. If the isolating resistor was not there, the heat sense would not detect 120 VAC (grounded element). Understanding the distinction between voltage and voltage drop is critical to understanding this circuit algorithm. So study this concept well!

    in reply to: Sealed system charging #26920

    I’ve heard if the replacement drier that’s also the manufacturers appointed drier through the part number is slightly bigger,

    So the OEM replacement drier is physically a little larger than the original drier that came with the refrigerator?

    it won’t hurt the system to add an additional gram or ounce, t

    Be careful here. There’s a big difference in volume between a gram and an ounce. There are about 28 grams per ounce. So while adding an additional gram to a systemn is not a big deal, adding an additional ounce is huge.

    R600a systems are typically measured in grams. You have, what, about 55 grams of refrigerant, give or take? Other systems are measured in ounces. These system charges range from 5 to 7 oz. Let’s say it’s a 5 oz system. If you add an extra ounce, that’s a 20% overcharge!

    In general, if the answer to my first question is “yes”, then I would not vary from the label charge unless the manufacturer gives specific guidancw for this.

    in reply to: Variable Thermostat #26910

    Hi Jessica, are you referring to a mechanical thermostat or an oven that uses an RTD?

    The old skool mechanical thermostats used a gas filled bourdon tube connected to the thermostat body. The gas in the tube expands and contracts in response to temperature. The expanding/contracting gas opens and closes contacts inside the thermostat body, thus controlling power to the heating element or gas ignitor.

    If that’s not what you’re after, let me know.

    in reply to: Basic Electricity #26861

    The main take away from that section is the paragraph right above the gauge table. Note particularly the injunction against joining copper and aluminum wires.

    Wire GAUGE is inversely related to wire DIAMETER. The higher the gauge, the smaller the diameter. Wire gauges are stamped on the insulation. It’s good to have a familiarly with these things since there are lots of wires inside an appliance!

    Ampacity– the amount of amps a particular gauge wire can carry– is also inversely related to gauge. The higher the gauge, the less amps it can carry.

    in reply to: Module 2 unit 2 Molex connector question #26846

    . Do you assume that all of those are connected to the control board? or to each other? In other words, do you have to have the appliance torn apart to fully understand which connetor connects to what?

    “Molex” is the name of a company that has become used as a generic. Like Kleenex or Coke. So it’s a generic term used to refer to any type of multi wire connection, whether that connection is at a board or at a door hinge or wherever.

    The relative location of molex connectors is usually shown on the schematic or wiring diagram. GE is especially good at denoting molex connections anywhere they occur right on the schematic without having to use messy wiring diagrams. They do this because someone at GE at one time understood that any molex connector is a weak point in a circuit because it is subject to corrosion, mechanical failure, etc. that wires are not vulnerable to.

    in reply to: Module 4 unit 10 #26823

    I just had a question in regard to thermal fuses vs thermal cut outs.

    Watch the first minute of the first video in Module 4, Unit 5. Thermal fuses and thermal cutoffs (TCO) are different names for the same physical component.

    There is a distinction between TCOs and hi limits. Hi limits are bimetals and function differently from TCOs.

    Even though TCOs and hi limits are in different electrical circuits, they are still physical components placed in locations in the dryer where they can monitor and respond to overheat conditions.

    The big electrical thing that both TCOs and hi limits have in common is both are switches. The whole purpose of a switch is to control the power supply to a load. In an overheat condition, these switches do what switches do: they switch! In this case, they go open, killing power to the load they control, be it motor or heating circuit.

    in reply to: Testing Evap fans with a 9v battery #26805

    Ok, so in DC circuits when you measure +5VDC you’re really measuring that sucking force of the positive polarity whereas in AC you’re measuring the “pushing” force, is that a good way to put it?

    Not quite. Remember that electrons are pushed a circuit around by a voltage DIFFERENCE between two points in a circuit. Those two points creating the voltage difference in the circuit are the power supply. In a complete circuit with a driving voltage difference, electrons will move in accordance with the same principle: like charges repel, opposite charges attract. This fundamental law of electricity is called “electrostatic attraction” or “electrostatic repulsion.”

    Electrically, the only distinction between AC and DC circuits is that the DC power supply polarity does not change over time. So the negatively charged electrons will always travel in the same direction in the circuit: from the relatively negative polarity to the relatively more positive polarity. In AC circuits, the electrons “jiggle” back and forth as the polarity of the voltage supply switches 120 times a second (in a 60 Hz supply, which is North American grid standard power).

    So whether you think of it as pushing or sucking, electrically AC and DC voltage supplies operate on electrons in the exact same way: electrostatic attraction and repulsion.

    For example, if I were to measure voltage between the red wire and some other random neutral, I’d see +5 VDC (or whatever the power supply voltage is) and if I do the same for the white wire and some other random neutral I’d see 0v? or would it be the other way around? Thanks!

    Remember that the definition of voltage is the DIFFERENCE in potential between TWO points IN THE SAME CIRCUIT and FROM THE SAME POWER SUPPLY.

    How many leads does it take to measure voltage? Two, right? So we do not measure voltage “at a point” in a circuit. We measure voltage BETWEEN TWO POINTS in a circuit. The SAME circuit. The circuit powered by the SAME power supply.

    DC and AC circuits function independently from each other because they use different voltage supplies. DC ground (or common or negative terminal of the battery) is NOT AC Neutral or chassis ground. If you’re measuring DC voltage, you need a DC reference. It makes no sense electrically to measure the voltage difference between a DC circuit and an AC circuit.

    In the above exaxmple it seems that VCC is DC ground?

    In DC circuits, VCC and DC ground are the two sides of the voltage supply. In AC circuits, the two sides of the voltage supply are L1 and Neutral or L1 and L2.

    VCC also goes by various other names. We discuss those in this video: https://appliantology.org/topic/101611-strip-circuits-dc-terminology/

    Making more sense?

    in reply to: Testing Evap fans with a 9v battery #26802

    Also remember that when we talk about current, we’re talking about the movement of negatively charged electrons directed in a wire. This is key to understanding the function of DC ground or DC negative pole in a circuit’s power supply. The DC ground (or common or negative terminal of the battery) becomes a reservoir of electrons that are pulled out of ground (common/negative terminal) by the positive polarity. I think of it as the positive polarity (DC supply) as “sucking” electrons out of the negative pole (common, DC ground, negative polarity) and draws them to itself because, in electricity, opposite polarities are attracted to each other. Same polarities repel each other. So negatively electrons are always going to be attracted to a relatively more positive charge.

    in reply to: Testing Evap fans with a 9v battery #26800

    Why does the white wire get the power from the battery if thats DC Ground?

    You need a complete circuit from the power supply, through the load, and back to the SAME power supply for electrons to move and make the load do its work. If you’re going to cheat a load, you have to supply your own DC power supply– that means DC voltage supply AND DC ground. Both need to come from the same power supply source. In this case of cheating a BLDC motor with a 9 volt battery, that means the battery must supply BOTH DC voltage supply AND DC ground. Hence the white wire connected to the negative terminal of the battery.

    If you’re still confused, you may find it helpful to attend the upcoming Live Dojo workshop on 12/21. We have live discussions about all things pertaining to appliance repair, current repair problems and questions about fundamentals of circuits and technology. Here’s the link to the next Live Dojo: https://appliantology.org/events/event/946-appliantology-live-dojo-saturday-12212024-10-am-et/

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